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我在写一个非常简单的随机漫游功能。整个代码如下。当前成本函数小于前一个时,我使用数组来跟踪参数值。但出于某种原因,跟踪输出的数组是重写?以前的条目。我认为它与将参数附加为“c”有关,因此存在内存分配问题,因为“c”是附加的而不是c的值,但我不知道如何解决这个问题,也不知道为什么它与成本函数值psi不同,后者按预期追加并保持其值。For循环写入数组中的以前条目的部分但不是全部
我想创造的东西,如:
input:
for n in N:
if cost < previous cost: keep current parameters
write current parameters & cost to tracking list
output:
n = 0, parameters = [1,2,3], cost = 4.5, track = [([1,2,3], 4.5)]
n = 1, parameters = [1.1,2.4,2.7], cost = 3.9, track = [([1,2,3], 4.5), ([1.1, 2.4, 2.7], 3.9)]
etc
代替,就是我得到的是
output:
n = 0, parameters = [1,2,3], cost = 4.5, track = [([1,2,3], 4.5)]
n = 1, parameters = [1.1,2.4,2.7], cost = 3.9, track = [([1.1,2.4,2.7], 4.5), ([1.1, 2.4, 2.7], 3.9)]
所以它取代了参数,但保持先前的费用。当跟踪功能在成功(成本较低)以外的情况下也会发生这种情况。
有帮助吗?
#pure random walk where all c parameters are randomly updated at once; no restrictions on pos/neg of parameters
del track
del bigtrack
c = [5,5,-5]
cp = c
kB = -8
M = 10
N = 5000
bigtrack = []
psip = cost(LN, LB, dldtN, dldtB, c[2], kB, c[0], c[1]) #cost using initialized parameters
for m in range(M):
track = []
for n in range(N):
for i in range(len(c)):
rand = np.random.uniform(-1,1)
c[i] = c[i] + rand
#print(c[i])
#print("parameters = ", c)
psi = cost(LN, LB, dldtN, dldtB, c[2], kB, c[0], c[1])
#print("new cost = ", psi)
if psi < psip:
cp = c
resp = res
psip = psi
track.append((c, psi))
print("tracking function: \n", track)
else:
c = cp #keep prior
res = resp
psi = psip
if psi <16:
print("VICTORY")
break
#print(track)
#if track != []:
bigtrack.append((track, m))
,这里是一个样本输出
tracking function:
[([4.145180382591114, 5.194803875207629, -5.77417154313107], 457.37070071446328)]
tracking function:
[([4.366620027701061, 5.610886161756634, -6.300451985366614], 457.37070071446328), ([4.366620027701061, 5.610886161756634, -6.300451985366614], 406.27520117896)]
tracking function:
[([4.294900222966394, 6.104004008230176, -6.636360393709489], 457.37070071446328), ([4.294900222966394, 6.104004008230176, -6.636360393709489], 406.27520117896), ([4.294900222966394, 6.104004008230176, -6.636360393709489], 377.1702411076343)]
啊!谢谢!修复它 –