postgresql计数子女数

Question

树无限深。例如：

+----+-------+--------------------+ 
| id | name | parent_id | value | 
+----+-------+--------------------+ 
| 1 | test1 |   | 0 | 
| 2 | test2 |  1  | 0 | 
| 3 | test3 |  2  | 5 | 
| 4 | test4 |  1  | 0 | 
| 5 | test5 |  4  | 5 | 
| 6 | test6 |  4  | 0 | 
| 7 | test7 |  6  | 10 | 
+----+-------+--------------------+ 

我想获得一个孩子的总价值。 就像这样：

+----+-------+--------------------+ 
| id | name | parent_id | value | 
+----+-------+--------------------+ 
| 1 | test1 |   | 20 | = test2.value + test4.value 
| 2 | test2 |  1  | 5 | = test3.value 
| 3 | test3 |  2  | 5 | 
| 4 | test4 |  1  | 15 | = test5.value + test6.value 
| 5 | test5 |  4  | 5 | 
| 6 | test6 |  4  | 10 | = test7.value 
| 7 | test7 |  6  | 10 | 
+----+-------+--------------------+ 

有什么建议吗？谢谢！

Answer 1

这里是希望能解决您的问题递归查询：

WITH RECURSIVE tree (id, parent_id, cnt) AS (
    -- start from bottom-level entries 
    SELECT id, parent_id, 0::bigint AS cnt 
    FROM tbl t 
    WHERE NOT EXISTS (
     SELECT id 
     FROM tbl 
     WHERE parent_id = t.id 
    ) 

    UNION ALL 

    -- join the next level, add the number of children to that of already counted ones 
    SELECT t.id, t.parent_id, tree.cnt + (
      SELECT count(id) 
      FROM tbl 
      WHERE parent_id = t.id 
     ) 
    FROM tbl t JOIN tree ON t.id = tree.parent_id 
) 
SELECT tree.id, max(tree.cnt) AS number_of_children 
FROM tree 
-- use the JOIN if you need additional columns from tbl 
-- JOIN tbl ON tree.id = tbl.id 
-- use the WHERE clause if you want to see root nodes only 
-- WHERE parent_id IS NULL 
GROUP BY tree.id 
ORDER BY tree.id 
; 

我做了一个SQLFiddle了。

Answer 2

见F.35.1.5。这里connectby功能例如：

http://www.postgresql.org/docs/current/static/tablefunc.html