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以我ANTLR语法,我有以下语句:ANTLR打印指数(在线)
@lexer::apifuncs
{
LEXER->rec->displayRecognitionError = recognition_error;
}
@parser::apifuncs
{
RECOGNIZER->displayRecognitionError = recognition_error;
}
C函数“recognition_error”(以处理由ANTLR抛出的识别错误)被定义为以下内容:
void recognition_error(pANTLR3_BASE_RECOGNIZER recognizer, pANTLR3_UINT8 *token_list)
{
pANTLR3_EXCEPTION ex;
pANTLR3_LEXER lexer;
pANTLR3_PARSER parser;
pANTLR3_TREE_PARSER tparser;
pANTLR3_INPUT_STREAM ins;
pANTLR3_INT_STREAM is;
pANTLR3_COMMON_TOKEN_STREAM cts;
pANTLR3_TREE_NODE_STREAM tns;
if (recognizer->type == ANTLR3_TYPE_LEXER)
{
lexer = (pANTLR3_LEXER) (recognizer->super);
ins = lexer->input;
is = ins->istream;
}
else if (recognizer->type == ANTLR3_TYPE_PARSER)
{
parser = (pANTLR3_PARSER) (recognizer->super);
cts = (pANTLR3_COMMON_TOKEN_STREAM)(parser->tstream->super);
is = parser->tstream->istream;
}
else if (recognizer->type == ANTLR3_TYPE_TREE_PARSER)
{
tparser = (pANTLR3_TREE_PARSER) (recognizer->super);
tns = tparser->ctnstream->tnstream;
is = tns->istream;
}
else
{
printf("UNKNOWN ERROR!\n");
return;
}
printf("INFO <%d> * <%d> * <%d> * <%d>\n", recognizer->state->exception->line, recognizer->state->exception->charPositionInLine, recognizer->state->exception->index, ((pANTLR3_COMMON_TOKEN) recognizer->state->exception->token)->getCharPositionInLine);
}
每次我使用这个语法来分析,有一个错误的字符一些文本,功能“recognition_error”不打印炭的指数发现错误的地方(它只是打印垃圾,如-1或0)。
如何修正这个语法和/或C函数以打印正确的索引?
谢谢迈克! MySQL Workbench项目中的错误处理代码有助于澄清如何为我的项目实现它。 – user5793565