我有2个类,DigitMath.java和DigitMathRunner.java,实验所需的设置使用DigitMathRunner作为DigitMath的启动程序。从我的平均值/输出返回0.0's返回
我的代码的目的是显示数字的平均值,然后将其输出到一个句子中。 编译器不给出错误,但输出如下。
> >
run DigitMathRunner
234 has a digit average of 0.0
10000 has a digit average of 0.0
111 has a digit average of 0.0
9005 has a digit average of 0.0
84645 has a digit average of 0.0
8547 has a digit average of 0.0
123456789 has a digit average of 0.0
>
这里是DigitMath.java
import static java.lang.System.*;
public class DigitMath
{
private int number;
private int count;
private int s;
private int sum;
private int input;
private double average;
public DigitMath()
{
number = 0;
sum=0;
count = 0;
input = 0;
}
public DigitMath(int s)
{
number = s;
input = s;
}
public void setNums(int s)
{
number = s;
input = s;
}
public int sumDigits()
{
int sum=0;
while(input > 0)
{
sum += input % 10;
input /= 10;
}
return sum;
}
public int countDigits()
{
count = (int)(Math.log10(number)+1);
return count;
}
public double averageDigits()
{
double average = sum/count;
return average;
}
public int output()
{
System.out.println(""+number +" has a digit average of "+""+average);
return number;
}
}
和下一个代码块是转轮的代码。
//Name - Seth Garcia
//Date - 5/12/16
//Class - 3rd Period Monaghan
//Lab - DigitMath
import static java.lang.System.*;
public class DigitMathRunner
{
public static void main(String args[])
{
DigitMath test = new DigitMath();
test.setNums(234);
test.sumDigits();
test.countDigits();
test.averageDigits();
test.output();
test.setNums(10000);
test.sumDigits();
test.countDigits();
test.averageDigits();
test.output();
test.setNums(111);
test.sumDigits();
test.countDigits();
test.averageDigits();
test.output();
test.setNums(9005);
test.sumDigits();
test.countDigits();
test.averageDigits();
test.output();
test.setNums(84645);
test.sumDigits();
test.countDigits();
test.averageDigits();
test.output();
test.setNums(8547);
test.sumDigits();
test.countDigits();
test.averageDigits();
test.output();
test.setNums(123456789);
test.sumDigits();
test.countDigits();
test.averageDigits();
test.output();
}
}
也是我在计算机科学1高中,如果我的代码是坏的,请告诉我如何改进,谢谢。
'sum /(1.0)* count;' - better'sum /(double)count;' – Thomas
我忘记了一些括号,所以看起来更干净 –