因为借用而无法移出`req`

Question

我在玩Rust和tiny-http。我已经创造了一种我与请求的报头搞乱，然后发送响应函数：

fn handle_request(req: Request) { 
    let headers = req.headers(); 
    // working with headers 
    let res = Response::from_string("hi"); 
    req.respond(res); 
} 

它失败，错误：

main.rs:41:5: 41:8 error: cannot move out of `req` because it is borrowed 
main.rs:41  req.respond(res); 
       ^~~ 
main.rs:27:19: 27:22 note: borrow of `req` occurs here 
main.rs:27  let headers = req.headers(); 
          ^~~ 
error: aborting due to previous error 

所以我有点明白req.headers()接受&self这执行借款req和req.respond()“移动”req，因为它接受self。我不确定我应该在这里做什么，有人能帮我理解吗？

Answer 1

在移动该值之前，您必须确定借款已结束。为适应您的代码：

fn handle_request(req: Request) { 
    { 
     let headers = req.headers(); 
     // working with headers 
    } 
    let res = Response::from_string("hi"); 
    req.respond(res); 
} 

的借将仅持续在函数的顶部块，所以该块结束后，你可以自由地移动res。