在我开始之前,我是一名C初学者,我正在尝试做一些可能是错误的openCL工作。下面是我的内核代码:openCL Long溢出
__kernel void collatz(__global int* in, __global int* out)
{
uint id = get_global_id(0);
unsigned long n = (unsigned long)id;
uint count = 0;
while (n > 1) {
if (n % 2 == 0) {
n = n/2;
} else {
if(n == 1572066143) {
unsigned long test = n;
printf("BEFORE - %lu\n", n);
test = (3 * test) + 1;
printf("AFTER - %lu\n", test);
n = (3 * n) + 1;
} else {
n = (3 * n) + 1;
}
}
count = count + 1;
}
out[id] = count;
}
和输出:
BEFORE - 1572066143
AFTER - 421231134
对我来说,它看起来像n为四溢,但我想不出为什么它正在发生。
有趣的是,如果我创建一个新的变量来存储与n相同的值,那么它似乎正常工作。
unsigned long test = 1572066143;
printf("BEFORE - %lu\n", test);
test = (3 * test) + 1;
printf("AFTER - %lu\n", test);
输出:
BEFORE - 1572066143
AFTER - 4716198430
正如我所说的,我一个C初学者,所以我可以做一些非常愚蠢的!任何帮助将不胜感激,因为我已经把我的头发拉出几个小时了!
感谢, 斯蒂芬
更新:
这里是我的主代码的情况下,我做的事情上月底愚蠢:
int _tmain(int argc, _TCHAR* argv[])
{
/*Step1: Getting platforms and choose an available one.*/
cl_uint numPlatforms; //the NO. of platforms
cl_platform_id platform = NULL; //the chosen platform
cl_int status = clGetPlatformIDs(0, NULL, &numPlatforms);
cl_platform_id* platforms = (cl_platform_id*)malloc(numPlatforms* sizeof(cl_platform_id));
status = clGetPlatformIDs(numPlatforms, platforms, NULL);
platform = platforms[0];
free(platforms);
/*Step 2:Query the platform and choose the first GPU device if has one.*/
cl_device_id *devices;
devices = (cl_device_id*)malloc(1 * sizeof(cl_device_id));
clGetDeviceIDs(platform, CL_DEVICE_TYPE_GPU, 1, devices, NULL);
/*Step 3: Create context.*/
cl_context context = clCreateContext(NULL, 1, devices, NULL, NULL, NULL);
/*Step 4: Creating command queue associate with the context.*/
cl_command_queue commandQueue = clCreateCommandQueue(context, devices[0], 0, NULL);
/*Step 5: Create program object */
const char *filename = "HelloWorld_Kernel.cl";
std::string sourceStr;
status = convertToString(filename, sourceStr);
const char *source = sourceStr.c_str();
size_t sourceSize[] = { strlen(source) };
cl_program program = clCreateProgramWithSource(context, 1, &source, sourceSize, NULL);
status = clBuildProgram(program, 1, devices, NULL, NULL, NULL);
/*Step 7: Initial input,output for the host and create memory objects for the kernel*/
cl_ulong max = 2000000;
cl_ulong *numbers = NULL;
numbers = new cl_ulong[max];
for (int i = 1; i <= max; i++) {
numbers[i] = i;
}
int *output = (int*)malloc(sizeof(cl_ulong) * max);
cl_mem inputBuffer = clCreateBuffer(context, CL_MEM_READ_ONLY | CL_MEM_COPY_HOST_PTR, max * sizeof(cl_ulong), (void *)numbers, NULL);
cl_mem outputBuffer = clCreateBuffer(context, CL_MEM_WRITE_ONLY, max * sizeof(cl_ulong), NULL, NULL);
/*Step 8: Create kernel object */
cl_kernel kernel = clCreateKernel(program, "collatz", NULL);
/*Step 9: Sets Kernel arguments.*/
status = clSetKernelArg(kernel, 0, sizeof(cl_mem), (void *)&inputBuffer);
// Determine the size of the log
size_t log_size;
clGetProgramBuildInfo(program, devices[0], CL_PROGRAM_BUILD_LOG, 0, NULL, &log_size);
// Allocate memory for the log
char *log = (char *)malloc(log_size);
// Get the log
clGetProgramBuildInfo(program, devices[0], CL_PROGRAM_BUILD_LOG, log_size, log, NULL);
// Print the log
printf("%s\n", log);
status = clSetKernelArg(kernel, 1, sizeof(cl_mem), (void *)&outputBuffer);
/*Step 10: Running the kernel.*/
size_t global_work_size[] = { max };
status = clEnqueueNDRangeKernel(commandQueue, kernel, 1, NULL, global_work_size, NULL, 0, NULL, NULL);
/*Step 11: Read the data put back to host memory.*/
status = clEnqueueReadBuffer(commandQueue, outputBuffer, CL_TRUE, 0, max * sizeof(cl_ulong), output, 0, NULL, NULL);
return SUCCESS;
}
可能只是一个编译器错误,当我在自己的机器上运行相同的内核时,我得到了正确的结果。你在使用哪种OpenCL平台和设备?你尝试过不同的吗? – jprice
感谢您的回应并在您的最后尝试。我正在使用AMD SDK。我已经在我的英特尔集成显卡以及我的AMD显卡280x上尝试过它,但都产生了错误的结果。我可能会尝试在AMD开发人员论坛上提出同样的问题。 – stephenheron