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我已经注意到一些不寻常的行为时,试图适应一些嘈杂的数据:当我改变阵列的长度,我得到疯狂不同的拟合。奇怪的行为在scipy.optimize.leastsq
import numpy as np
import matplotlib.pyplot as plt
# set up true function and "measured" data
x = np.linspace(0, 6e-2, 500);
A, k, theta = 10, 1.0/3e-2, np.pi/6;
y_true = A * np.sin(2 * np.pi * k * x + theta);
y_meas = y_true + 2*np.random.randn(x.size);
plt.plot(x, y_meas);
plt.plot(x, y_true);
plt.show()
哪个给出了这样的形象:
我已经创造了一些辅助功能,然后我做了最小二乘法拟合:
# residual function, e_i
def residuals(p, y, x):
A, k, theta = p;
err = y - A * np.sin(2 * np.pi * k * x + theta);
return err;
def peval(x, p):
return p[0] * np.sin(2 * np.pi * p[1] * x + p[2]);
# starting values of A, k and theta
p0 = [12, 1/2.3e-2, np.pi/3];
print(np.array(p0));
# do least squares fitting
from scipy.optimize import leastsq
plsq = leastsq(residuals, p0, args=(y_meas, x));
print(plsq[0]); print(np.array([A, k, theta]));
绘制这给:
plt.plot(x, peval(x, plsq[0]))
plt.plot(x, y_meas,'ro')
plt.plot(x, y_true);
plt.title('Least-squares fit to noisy data');
plt.legend(['Fit', 'Noisy', 'True']);
当我改变我的设置为:
x = np.linspace(0, 18e-2, 500);
A, k, theta = 10, 1.0/3e-2, np.pi/6;
y_true = A * np.sin(2 * np.pi * k * x + theta);
y_meas = y_true + 2*np.random.randn(x.size);
(即我三倍的时间,我衡量)的长度,然后运行该代码的其余部分,我得到的配合变为:
我试图单步调试代码,但不能拿出这个例子失败的原因。