2012-07-04 70 views
1

我将Mat对象推入std :: vector。将OpenCv Mat插入到C++ std :: vector

但是,当我尝试访问元素(Mat)后,它并没有给我推送的图像,这取决于frameOrientation。

例如,在下面的情况下,我得到“after_push_rotated2.jpg”与“before_push_rotated3.jpg”相同,不应该是这样。

如果我将frameOrientation设置为全部“2s”或“4s”,“after_push_rotated1/2/3.jpg”全部相同并且等于“before_push_rotated3.jpg”。

这里有什么问题?

#include <cv.h> 
#include <cxcore.h> 
#include <highgui.h> 
#include <iostream> 
#include <vector> 

using namespace cv; 
using namespace std; 

vector<Mat> checkOrientationAndRotate() 
{ 
    Mat frame1 = imread("1.jpg"); 
    Mat frame2 = imread("2.jpg"); 
    Mat frame3 = imread("3.jpg"); 



    vector<Mat> frameList; 
    vector<Mat> frameList_rotated; 

    frameList.push_back(frame1); 
    frameList.push_back(frame2); 
    frameList.push_back(frame3); 

    Mat transposedFrame; 
    Mat rotatedFrame; 

    int i=0; 
    for (vector<Mat>::iterator iter = frameList.begin(); iter != frameList.end(); iter++) 
    { 
     //Check for orientation of that frame 
     int frameOrientation; 
     if (i==0) frameOrientation = 1; 
     if (i==1) frameOrientation = 2; 
     if (i==2) frameOrientation = 4; 

     switch (frameOrientation) 
     { 
     case 1: //1 - no rotate 
      rotatedFrame = *iter; 
      break; 

     case 2: //2 - rotate it ACW 90 deg 
      transpose(*iter, transposedFrame); 
      flip(transposedFrame, rotatedFrame, 0); 
      break; 

     case 3: //3 - rotate it 180deg 
      flip(*iter, rotatedFrame, -1); 
      break; 

     case 4: //4 - rotate it CW 90 deg 
      transpose(*iter, transposedFrame); 
      flip(transposedFrame, rotatedFrame, 1); 
      break; 
     default: 
      break; 
     } 

     //Check frame before pushing into vector 
     if (i==0) imwrite("before_push_rotated1.jpg",rotatedFrame); 
     if (i==1) imwrite("before_push_rotated2.jpg",rotatedFrame); 
     if (i==2) imwrite("before_push_rotated3.jpg",rotatedFrame); 

     frameList_rotated.push_back(rotatedFrame); 


     //Check frame after pushing into vector. 
     //Depending on the frameorientation, the frames are not the frames pushed in earlier! 
     int n=0; 
     for (vector<Mat>::iterator iter = frameList_rotated.begin(); iter != frameList_rotated.end(); iter++) 
     { 
      Mat frame = *iter; 
      if (n==0) imwrite("after_push_rotated1.jpg",frame); 
      if (n==1) imwrite("after_push_rotated2.jpg",frame); 
      if (n==2) imwrite("after_push_rotated3.jpg",frame); 
      n++; 
     } 

     i++; 
     } //for 

     return frameList_rotated; 

} 

void main() 
{ 
    vector<Mat> frameList_rotated = checkOrientationAndRotate(); 
} 

回答

7

[我没有使用OpenCV的随时随地最近,所以我可能是错的,请让我知道,如果我:)]

Mat代表(有点)像头,而不是图像数据。 OpenCV在内部维护一个引用计数机制,以避免在不同区域复制大量的图像像素数据。意思是说,当你说:

Mat a = b; // Only headers are copied, both a and b refer to the same image. 

在上述情况下,如果修改b,该变化将在a体现为好。你需要在这种情况下使用什么是:

Mat a = b.clone(); 

关于你的情况,我真的觉得下面的行应该可以解决问题(如果没有,有可能是一些其他问题的控制流,嘿嘿):

尝试更换:

Mat transposedFrame; 
Mat rotatedFrame; 

有:

//create a new image, not just the headers.. 
Mat transposedFrame(Size(image_width, image_height), image.type()); 
Mat rotatedFrame(Size(image_width, image_height), image.type()); 
+0

非常感谢您解释Mat如何工作。我一直都有错误的理解!顺便说一句,我通过将“transposedFrame”和“rotatedFrame”的声明转换为“for”循环来解决这个问题。 – seveleven

+0

很高兴知道它有帮助,而且我的想法并没有随着时间而消失。:) – SuperSaiyan