TSQL查询 - 列到行

Question

我有以下几点。

USE [tempdb] 
GO 

CREATE TABLE #Table (id int, row# int, Info varchar(10), 
         clm11 varchar(10), 
         clm21 varchar(10), 
         clm31 varchar(10), 
         clm41 varchar(10), 
         clm51 varchar(10), 
          clm12 varchar(10), 
          clm22 varchar(10), 
          clm32 varchar(10), 
          clm42 varchar(10), 
          clm52 varchar(10), 
           clm13 varchar(10), 
           clm23 varchar(10), 
           clm33 varchar(10), 
           clm43 varchar(10), 
           clm53 varchar(10)) 
INSERT INTO #Table 
SELECT 1, 100, 'Text', 'Col1', 'Col2', 'Col3', 'Col4', 'Col5','Col11', 'Col12', 'Col13', 'Col14', 'Col15','Col21', 'Col22', 'Col23', 'Col24', 'Col25' 
UNION ALL 
SELECT 2, 100, 'Text', 'Col1', 'Col2', 'Col3', 'Col4', 'Col5', NULL, NULL, NULL, NULL, NULL,'Col21', 'Col22', 'Col23', 'Col24', 'Col25' 
UNION ALL 
SELECT 3, 100, 'Text', 'Col1', 'Col2', 'Col3', 'Col4', 'Col5','Col11', 'Col12', 'Col13', 'Col14', 'Col15', NULL, NULL, NULL, NULL, NULL 
UNION ALL 
SELECT 4, 100, 'Text', 'Col1', 'Col2', 'Col3', 'Col4', 'Col5', NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL 
UNION ALL 
SELECT 5, 100, 'Text', NULL, NULL, NULL, NULL, NULL, 'Col11', 'Col12', 'Col13', 'Col14', 'Col15', 'Col21', 'Col22', 'Col23', 'Col24', 'Col25' 
UNION ALL 
SELECT 6, 100, 'Text', NULL, NULL, NULL, NULL, NULL, 'Col11', 'Col12', 'Col13', 'Col14', 'Col15', NULL, NULL, NULL, NULL, NULL 
UNION ALL 
SELECT 7, 100, 'Text', NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL, 'Col21', 'Col22', 'Col23', 'Col24', 'Col25' 

SELECT * FROM #Table 


/* Desired output 

ID Clm1 Clm2 Clm3 Clm4 Clm5 
1 Col1 Col2 Col3 Col4 Col5 
1 Col11 Col12 Col12 Col14 Col15 
1 Col21 Col22 Col23 Col24 Col25 
2 Col1 Col2 Col3 Col4 Col5 
2 Col21 Col22 Col23 Col24 Col25 
3 Col1 Col2 Col3 Col4 Col5 
3 Col11 Col12 Col13 Col14 Col15 
4 Col1 Col2 Col3 Col4 Col5 
5 Col11 Col12 Col13 Col14 Col15 
5 Col21 Col22 Col23 Col24 Col25 
6 Col11 Col12 Col13 Col14 Col15 
7 Col21 Col22 Col23 Col24 Col25 

*/ 


--- My Try 
SELECT Id, FieldCode, FieldValue 

FROM (SELECT id, clm11, clm21, clm31, clm41, clm51, clm12, clm22, clm32, clm42, clm52, clm13, clm23, clm33, clm43, clm53 FROM #Table) MyTable 

UNPIVOT 
(FieldCode FOR FieldCodes IN (clm11, clm21, clm31, clm41, clm12, clm22, clm32, clm42, clm13, clm23, clm33, clm43))AS CODE 

UNPIVOT 
(FieldValue FOR FieldValues IN (clm51, clm52, clm53))AS FieldValues 
WHERE RIGHT(FieldCodes,1) = RIGHT(FieldValues,1) 


DROP TABLE #Table 

我试图把ID和Clm11到Clm53（组5列），如果一组（5中校的）有值（非空集），把它们放在一个单独的记录ID为沿如“所需输出”部分所示。我刚刚显示了15列（Clm11-Clm51，Clm12-Clm52和Clm13-Clm53），但可以有更多的设置。

请帮忙。

TEMP更新：

select * 
from (select id, 
      (case when n = 1 then clm11 
        when n = 2 then clm21 
        when n = 3 then clm31 
        when n = 4 then clm41 
        when n = 5 then clm51 
       end) as col1, 
       (case when n = 1 then clm12 
        when n = 2 then clm22 
        when n = 3 then clm32 
        when n = 4 then clm42 
        when n = 5 then clm52 
       end) as col2, 
       (case when n = 1 then clm13 
        when n = 2 then clm23 
        when n = 3 then clm33 
        when n = 4 then clm43 
        when n = 5 then clm53 
       end) as col3 
     from #table t cross join 
      (select 1 as n union all select 2 union all select 3 union all select 4 union all select 5) n 
    ) t 
where coalesce(col1, col2, col3) is not null; 

Answer 1

我认为你可以只是由一系列union all做到这一点：

select id, Col11, Col12, Col13, Col14, Col15 
from #table 
where col11 is not null or col12 is not null or col13 is not null or 
     col14 is not null or col15 is not null 
union all 
select id, Col21, Col22, Col23, Col24, Col25 
from #table 
where col21 is not null or col22 is not null or col23 is not null or 
     col24 is not null or col25 is not null 
union all 
select id, Col31, Col32, Col33, Col34, Col35 
from #table 
where col31 is not null or col32 is not null or col33 is not null or 
     col34 is not null or col35 is not null; 

编辑：

是的，有与处理此问题的方法一个表扫描。这个想法是使用一个单独的柜台表和大量的病例陈述。下面是代码的结构：

select * 
from (select id, 
      (case when n = 1 then col11 
        when n = 2 then col21 
        when n = 3 then col31 
       end) as col1, 
      . . . 
     from #table t cross join 
      (select 1 as n union all select 2 union all select 3) n 
    ) t 
where coalesce(col1, col2, col3, col4, col5) is not null; 

此使用子查询来定义列，所以where子句不必重复难看case逻辑。

编辑2：

完整的查询看起来像每次三项条款，而不是三个case语句 case语句：

select * 
from (select id, 
      (case when n = 1 then clm11 
        when n = 2 then clm12 
        when n = 3 then clm13 
       end) as col1, 
       (case when n = 1 then clm21 
        when n = 2 then clm23 
        when n = 3 then clm23 
       end) as col2, 
       (case when n = 1 then clm31 
        when n = 2 then clm32 
        when n = 3 then clm33 
       end) as col3, 
       (case when n = 1 then clm41 
        when n = 2 then clm42 
        when n = 3 then clm43 
       end) as col4, 
       (case when n = 1 then clm51 
        when n = 2 then clm52 
        when n = 3 then clm53 
       end) as col5 
     from t cross join 
      (select 1 as n union all select 2 union all select 3 union all select 4 union all select 5) n 
    ) t 
where coalesce(col1, col2, col3, col4, col5) is not null; 

的SQL小提琴是here。