组中的python列表值

Question

我读了一个文件并用关键字对它进行分组。我也有一个列表，如果列表中的值在组中，我该如何检查它？不只检查一个条目，检查列表中的所有条目。

示例但未对照组检查列表。我不想写任何或任何blabla。

hosts = ['blabla.dyndns.org','blabla1.dyndns.org'] 
    with open(testfile,'r') as f: 
     for key,group in it.groupby(f,lambda line: line.startswith('[hosts]')): 
      if not key: 
       group = list(group) 
       if any("blabla.dyndns.org" in s for s in group) or any("blabla.dyndns.org" in s for s in group): 
        print 'yes' 
       else: 
        print 'no' 

谢谢，问候。

---

我想脚本，我可以在例如更改某些主机的协议。

import itertools as it 
testfile='blabla.txt' 

hosts = set(['blabla.dyndns.org','blabla1.dyndns.org']) 

with open(testfile,'r') as f: 
    for key,group in it.groupby(f,lambda line: line.startswith('[host]')): 
     if not key: 
      group = set(group) 
      if group & hosts: # set intersection 
       print '[host]\n' 
       for (i, item) in enumerate(group): 
        if 'protocol' in item: 
         group[i] = 'protocol  = udp\n' 
       j = ', '.join(group) 
       y = j.replace(", ", "") 
       print y 
      else: 
       print '[host]\n' 
       j = ', '.join(group) 
       y = j.replace(", ", "") 
       print y 

exit(0) 

不起作用。

Answer 1

使用设置路口：

hosts = set(['blabla.dyndns.org','blabla1.dyndns.org']) 
with open(testfile,'r') as f: 
    for key,group in it.groupby(f,lambda line: line.startswith('[hosts]')): 
     if not key: 
      group = set(group) 
      if group & hosts: # set intersection 
       print 'yes' 
      else: 
       print 'no'