我有一个函数可以动态地创建一个双元数组,它存储一串直到“gata”被引入的单词。二维数组的动态分配
的问题是,它崩溃,我觉得行
*(*words+*dim-1) = (char*)calloc(MAX_DIM,sizeof(char));
可能是problems.What的一个是错的这条线?
void read_words(char ***words,int *dim)
{
char buff[100];
*words = (char**)calloc(*dim,*dim*sizeof(char*));
while(strcmp(buff,"gata"))
{
printf("the new word : ");
scanf("%100s", buff);
if(strcmp(buff,"gata"))
{
dim++;
*words = (char**)realloc(words,*dim*sizeof(char*));
if(words == NULL)
{
printf("Memory allocation failed !\n");
exit(0);
}
*(*words+*dim-1) = (char*)calloc(MAX_DIM,sizeof(char));
strcpy(*(*words+*dim-1),buff);
}
}
}
int main()
{
char **words;
int i,dim = 0;
read_words(&words,&dim);
for (i = 0; i < dim; i++)
free(&words[i]);
free(words);
return 0;
}
是**新**存在c? – Fennekin
[请参阅此讨论,为什么不在'C'中投射'malloc()'和家族的返回值。](http://stackoverflow.com/q/605845/2173917)。 –
@Fennekin有没有nija编辑?我看不到'新'。 –