减少尝试的次数，除了python

Question

我正在写一个类似于诊断程序的程序，该程序运行一个测试，然后基于那个做更多的测试，所以这些大部分都在`try,except之内完成，并且有相当多的他们中的很多。有没有其他方法可以达到这个目的，但减少try except的数量？

这里是一个示例代码。

try: 
    treeinfo = subprocess.check_output(['C:\Python27\Scripts\scons.bat','-f' ,'scons_default.py' ,'--tree=all']) 
    print "\n" 
    print "Your machine type is ",platform.machine() 
     print "Compiling using default compiler\n" 
    print treeinfo 

except subprocess.CalledProcessError as e: 
    print "ERROR\n" 

try: 
    with open ('helloworld.exe')as f: 
     subprocess.call('helloworld.exe') 
     print"Build success" 
     log64 = subprocess.check_output(["dumpbin", "/HEADERS", "helloworld.exe"]) 
     if arch64 in log64: 
      print "Architecture of the compiled file is 64-bit " 
     elif arch32 in log64: 
      print "Architecture of the compiled file is 32-bit" 
except IOError as e: 
    print "Build failed\n" 


print "\n" 

上面的同一个代码（使用不同的文件名）重复，我知道这不是一个好的做法。我对python非常陌生，并且使用Google搜索没有给出任何有用的结果。

Answer 1

您可以将逻辑分成不同的功能，并在try块打电话给他们一个接一个：

def a(): 
    treeinfo = subprocess.check_output(['C:\Python27\Scripts\scons.bat','-f' ,'scons_default.py' ,'--tree=all']) 
    print "\n" 
    print "Your machine type is ",platform.machine() 
    print "Compiling using default compiler\n" 
    print treeinfo 

def b(): 
    subprocess.call('helloworld.exe') 
    print"Build success" 

def c(): 
    log64 = subprocess.check_output(["dumpbin", "/HEADERS", "helloworld.exe"]) 
    if arch64 in log64: 
     print "Architecture of the compiled file is 64-bit " 
    elif arch32 in log64: 
     print "Architecture of the compiled file is 32-bit" 

def try_these(funs, catch): 
    for fun in funs: 
     try: 
      fun() 
     except catch: 
      print 'ERROR!' 

try_these([a, b, c], catch=(IOError, OSError)) 

其中“钓”你要处理异常的元组。