Sprite bucketImage,background,r1,r2,r5, r10,r20,r50,r100,r200,r500,k1,k2,k5,k10,k20,k50;Sprites数组合并渲染精灵的时间
我在名为spawnRaindrop()的方法中创建对象。我有一组精灵,我想要在精灵周期中改变精灵,它现在可以工作,但是图像是相互融合的。
sprites = new Sprite[15];
r1 = new Sprite(atlas.findRegion("r1"));
r1.flip(false, true);
r2 = new Sprite(atlas.findRegion("r2"));
r2.flip(false, true);
r5 = new Sprite(atlas.findRegion("r5"));
r5.flip(false, true);
r10 = new Sprite(atlas.findRegion("r10"));
r10.flip(false, true);
r20 = new Sprite(atlas.findRegion("r20"));
r20.flip(false, true);
r50 = new Sprite(atlas.findRegion("r50"));
r50.flip(false, true);
r100 = new Sprite(atlas.findRegion("r100"));
r100.flip(false, true);
r200 = new Sprite(atlas.findRegion("r200"));
r200.flip(false, true);
r500 = new Sprite(atlas.findRegion("r500"));
r500.flip(false, true);
k1 = new Sprite(atlas.findRegion("k1"));
k1.flip(false, true);
k2 = new Sprite(atlas.findRegion("k2"));
k2.flip(false, true);
k5 = new Sprite(atlas.findRegion("k5"));
k5.flip(false, true);
k10 = new Sprite(atlas.findRegion("k10"));
k10.flip(false, true);
k20 = new Sprite(atlas.findRegion("k20"));
k20.flip(false, true);
k50 = new Sprite(atlas.findRegion("k50"));
k50.flip(false, true);
sprites[0] = r1;
sprites[1] = r2;
sprites[2] = r5;
sprites[3] = r10;
sprites[4] = r20;
sprites[5] = r50;
sprites[6] = r100;
sprites[7] = r200;
sprites[8] = r500;
sprites[9] = k1;
sprites[10] = k2;
sprites[11] = k5;
sprites[12] = k10;
sprites[13] = k20;
sprites[14] = k50;
创建游戏对象
private void spawnRaindrop() {
Rectangle raindrop = new Rectangle();
raindrop.x = MathUtils.random(0, 800 - 100);
raindrop.y = 480;
raindrop.width = 100;
raindrop.height = 100;
raindrops.add(raindrop);
lastDropTime = TimeUtils.nanoTime();
}
创建并绘制阵列精灵
game.batch.draw(bucketImage, bucket.x, bucket.y);
for (Rectangle raindrop : raindrops) {
for (int i = 0; i < sprites.length - 1; i++) {
game.batch.draw(sprites[i], raindrop.x, raindrop.y);
}
}
game.batch.end();
结果: 我附着的图像,它可以看出,图像上彼此
积累
那么你的问题到底是什么? –
@ Edvin Tenovim 如何通过game.batch.draw(sprites,raindrop.x,raindrop.y)绘制一个sprit数组;正确??? – upward