元组一个号码与数字蟒蛇的列表

Question

假设我有一个数字的数15和列表：

[5, 6, 7, 8] 

现在我想打一个元组列表像

[(15,6), (15,5), (15,7), (15,8)] 

一个人如何做那很快？

Answer 1

使用list comprehension：

list_of_nums = [5, 6, 7, 8] 
result = [(15, num) for num in list_of_nums] 

只要你有生产基于另一个序列的输出列表的过程中，通常一个列表解析可以做的工作。

演示：

>>> list_of_nums = [5, 6, 7, 8] 
>>> [(15, num) for num in list_of_nums] 
[(15, 5), (15, 6), (15, 7), (15, 8)] 

Answer 2

您也可以尝试zip功能

result = zip([15]*len(list_of_nums),list_of_nums) 

print(result) 
[(15, 5), (15, 6), (15, 7), (15, 8)]