蟒蛇比较的元组和字典

Question

我要比较两个组，并找到在蟒蛇的区别：

>>> mysql_orders = ((50434L, 5901L), (50733L, 5901L)) 
>>> opera_orders = [{'orderId': 'WEB050434', 'accountId': '00T001'}, {'orderId': 'WEB050733', 'accountId': '00T001'}, {'orderId': 'DOC075185', 'accountId': '00T001'}, {'orderId': 'WEB081859', 'accountId': '00T001'}] 

一个是元组列表和字典其中列表中的第一个项目可能是另外一个列表没有WEB/DOC前缀的orederId。

找不到mysql_orders列表中缺失的orderId的正确方法是什么？

Answer 1

使用正则表达式去除字母，但前提是数字总是晚一些，

import re 

mysql_orders = ((50434L, 5901L), (50733L, 5901L)) 

opera_orders = [{'orderId': 'WEB050434', 'accountId': '00T001'}, {'orderId': 'WEB050733', 'accountId': '00T001'}, {'orderId': 'DOC075185', 'accountId': '00T001'}, {'orderId': 'WEB081859', 'accountId': '00T001'}] 

mysql_orders = [element for tupl in mysql_orders for element in tupl] 

missing_order_ids = [opera_order['orderId'] for opera_order in opera_orders if long(re.split('\D+', opera_order['orderId'])[1]) not in mysql_orders] 

print missing_order_ids 

Answer 2

如果信件可能会或可能不会有，但领先的0是永远存在的，你可以用一组带：

from string import ascii_letters 

st = set(str(a) for a,_ in mysql_orders) 

missing = [d['orderId'] for d in opera_orders if not d['orderId'].strip(ascii_letters)[1:] in st] 

print(missing) 

['DOC075185', 'WEB081859'] 

如果前缀是永远存在的只是切片：

missing = [d['orderId'] for d in opera_orders if not d['orderId'][4:] in st]