我对编程PHP并不擅长,但仍然从中学习。
这是我的问题,我需要显示来自两个不同表的行的结果,研究过的东西并尝试过,但都失败了。用两张表显示多行
希望有人可以提供一些建议,我的代码行。
$query = "SELECT tblparent.*, tblchild.* FROM tblparent, tblchild* FROM tblparent";
$num_results = $result->num_rows;
$result = $mysqli->query($query);
if($num_results){
echo "<center><table border='1' id='members'>";
echo "<tr>";
echo "<th>Parent ID</th>";
echo "<th>Parent Firstname</th>";
echo "<th>Parent Lastname</th>";
echo "<th>Parent Middlename</th>";
echo "<th>Child ID</th>";
echo "<th>Child Firstname</th>";
echo "<th>Child Middlename</th>";
echo "<th>Child Lastname</th>";
echo "<th>Action</th>";
echo "</tr>";
while($row = $result->fetch_assoc()){
extract($row);
echo "<tr>";
echo "<td>{$Parent_ID}</td>";
echo "<td>{$PFname}</td>";
echo "<td>{$PLname}</td>";
echo "<td>{$PMname}</td>";
echo "<td>{$Child_ID}</td>";
echo "<td>{$CFname}</td>";
echo "<td>{$CMname}</td>";
echo "<td>{$CLname}</td>";
echo "<td>";
echo "<a href='#' onclick='delete_mem({$Parent_ID});'>Delete</a>";
echo "</td>";
echo "</tr>";
}
echo "</table>";
}
else{
echo "No records found.";
}
$result->free();
$mysqli->close();
只是为了确认,你试图从2个不同的数据库表中获取数据,并将它们放入一个HTML表格中? – 2014-09-26 00:03:16