php mysql查询字符串数组

Question

我正在建立一个字符串，我检查mysql数据库。

eg: 
formFields[] is an array - input1 is: string1 
array_push(strings, formFields) 
1st string and mysql query looks like this: 
"select * from my table where id in (strings)" 

formFields[] is an array - input2 is: string1, string2 
array_push(strings, formFields) 
2nd string and mysql query looks like this: 
"select * from my table where id in (strings)" 

formFields[] is an array - input3 is: string1, string2,string3 
array_push(strings, formFields) 
3rd string and mysql query looks like this: 
"select * from my table where id in (strings)" 

我会想添加单引号和逗号阵列，这样我有这样的字符串数组： “从我的表中选择*，其中ID在（‘STRING1’，‘字符串2’，” string3'）“

我试过使用数组implode，但仍然没有运气有任何想法？感谢

Answer 1

'SELECT ... WHERE id IN ("' . implode('","', $strings) . '")'; 

Answer 2

implode("','",$array); 

Answer 3

implode()是解决办法，但你不应该忘记转义数据：

$data = array(...); 
array_walk($data, function(&$elem, $key) { 
    $elem = mysql_real_escape_string($elem); 
}); 
$sql = 'SELECT ... id IN ("' . implode('", "', $data) . '");';