我正在尝试构建一个关于足球队的网页。需要中频功能的一些帮助
于是,我把信息在一个SQL文件,然后在XAMPP数据库。问题是,当我把对球员和教练这样的信息:http://i.imgur.com/6EuYNPh.png他们出现在“存储”部分和“奖杯”过,这使它看起来像恼人:P http://i.imgur.com/tht9vTP.png
所以我需要一个像一个代码如果市场价值或位置或出生地点=空,然后隐藏这些值(我的意思是隐藏:市场价值,位置等)我知道我必须在函数文件中使用IF函数。我尝试了一些,但实际上并没有工作。
准确的代码是什么,我必须使用,我应该把它放在哪里?
功能的文件是在这里:
<?php
//Position:
//function to generate the local navigation bar for the bookstore web application
function gen_navigation(){
include("dbconnect.php");
echo "<head>";
echo '<link rel="stylesheet" type="text/css" href="css/navigation.css" />';
echo "</head>";
$query="select * from categories";
$result=mysql_query($query);
echo "<div id=navcontainer>";
echo "<ul id=navlist>";
while($row=mysql_fetch_array($result)){
echo "<li>";
echo "<a href=items.php?categoryid=";
echo $row['categoryid'];
echo ">";
echo $row['name'];
echo "</a>";
echo "</li>";
}
echo "</ul>";
echo "</div>";
mysql_close();
}
//Position:
//function to display the new items. The layout is formated by using tables
//position:
//function to display the new items. The layout is formated by using tables
function showbooksbycat($categoryid=1,$offset=0,$limit=8){
if(empty($offset)){
$offset=0;
}
include("dbconnect.php");
$query="select * from items where categoryid=$categoryid order by isbn limit $offset,$limit";
$result=mysql_query($query);
echo "<br>";
while($row=mysql_fetch_array($result)){
echo "<table width=100% border=0>";
echo "<tr class=newitems>";
echo "<th>";
echo "Market Value".$row['market value'];
echo "</th>";
echo "<th>";
echo $row['name'];
echo "</th>";
echo "</tr>";
echo "<tr>";
echo "<td width=100>";
echo "<img src=pictures/".$row['picture'].">";
echo "</td>";
echo "<td align=left>";
echo "<p class=itemmaininf>";
echo "<b>Name:</b> ".$row['name']."<br>";
echo "<b>Position:</b> ".$row['position']."<br>";
echo "<b>Place Of Birth:</b> ".$row['birthplace']."<br>";
echo "<b>Date Of Birth:</b> ".$row['date']."<br>";
echo "<b>Previous Clubs:</b> ".$row['previous clubs']."<br>";
echo "</p>";
echo "<p class=footitem>";
echo "</p>";
echo "</td>";
echo "</tr>";
echo "</table>";
echo "<br>";
}
mysql_close();
}
function nav($categoryid=1,$offset=0,$limit=8){
include("dbconnect.php");
$query="select * from items where categoryid=$categoryid";
$result=mysql_query($query);
$numrows=mysql_num_rows($result);
echo " ";
if($offset>0){
echo "<a href=items.php?categoryid=".$categoryid."&offset=".($offset-$limit);
echo ">";
echo "<img border=0 src=pictures/prev.gif></a>";
echo " ";
}
if($offset+$limit<$numrows){
echo "<a href=items.php?categoryid=".$categoryid."&offset=".($offset+$limit);
echo ">";
echo "<img border=0 src=pictures/next.gif></a>";
}
echo "</font>";
}
?>
你不需要一个回波的每一行。 – 2014-09-25 21:21:40
你试了一些东西,但实际上并没有工作。那可能是什么......?更好地了解你做错了什么,然后让别人给你答案... – 2014-09-25 21:22:09
'所以我需要一个代码,如中频市场价值或位置或出生地点=空,'但没有像代码中的东西你发布了,所以这些代码与这个问题无关。 – developerwjk 2014-09-25 21:23:00