问题和如果语句包含一个字符串在C++

-2

#include <iostream> 

using namespace std; 

int main(){ 

    cout << endl; 
    cout << "Welcome to the wonderful world of a spy" << endl; 
    cout << "Today we are to decode some information that has been provided." <<endl; 
    string response; 
    cout << "Are you ready?" << endl; 
    cin >> response; 
    if (response == "yes", "y", "Yes", "Y"){ 
     cout << "Alright, let's go!!!" << endl; 
    } 
    else { 
     cout << "Well, too bad. We are going to do it anyways." << endl; 
    } 
}

Exact Code这是我的代码到目前为止。我不能说“好吧，我们走吧!!!我做错了什么？问题和如果语句包含一个字符串在C++

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2017-09-26 WinryKate

让我们从一个实际的代码片段开始，而不是一个截图。代码进入你的问题。 – Thebluefish

请不要试图猜测语法。这个'if'语句的结果是''Y''的评估，它总是'true'（剩下的被丢弃，它们没有副作用）。请获得[好书]（https://stackoverflow.com/questions/388242/the-definitive-c-book-guide-and-list） – Rakete1111

您的if语句条件是错误的

if(response == "yes" || response == "y" || response == "Yes" || response == "Y") 
    { 
     //then do whatever... 
    }else{ 
     //do it anyway... 
    }

来源

2017-09-26 19:47:32 kman123

行if (response == "yes", "y", "Yes", "Y")不会做你认为它的作用。逗号运算符评估它的每个操作数，丢弃结果在左边，右边的结果是表达式的结果，所以你写的东西等于if ("Y")，你需要使用逻辑OR运算符来组合你的不同情况，就像这样if (response == "yes" || response == "y" || response == "Yes" || response == "Y")

来源

2017-09-26 19:47:14

问题和如果语句包含一个字符串在C++

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