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我想让矩形在屏幕上上下移动。但是,当我按下键使其升高或降低时,我必须每次不断按下它使其移动。我解释pygame.KEYDOWN
的方式是,我可以按住所需的键,矩形会移动,直到我释放键。Pygame KEYDOWN不工作
代码键按下:
while True:
for event in pygame.event.get():
# all keys
keys = pygame.key.get_pressed()
# quit game
if event.type == pygame.QUIT or keys[pygame.K_ESCAPE]:
pygame.quit()
quit()
# check key down presses
elif event.type == pygame.KEYDOWN:
# left paddle
if keys[pygame.K_q]:
left.move(-30)
if keys[pygame.K_a]:
left.move(30)
# right paddle
if keys[pygame.K_p]:
right.move(-30)
if keys[pygame.K_l]:
right.move(30)
# user let up on a key
elif event.type == pygame.KEYUP:
if event.key == keys[pygame.K_q] or event.key == keys[pygame.K_a]:
left.move(0)
elif event.key == pygame.K_p or event.key == pygame.K_l:
right.move(0)
# call animation function
draw()
# FPS
clock.tick(120)
的left
和right
对象从下面的类来:
import pygame
class Paddle:
def __init__(self, screen, h, w, left):
self.screen = screen
self.width = w
self.y = h/2
self.pad_width = 10
self.pad_height = 70
if left:
self.x = self.pad_width/2
else:
self.x = self.width - self.pad_width * 1.5
def show(self):
WHITE = (255, 255, 255)
rect = pygame.Rect(self.x, self.y, self.pad_width, self.pad_height)
pygame.draw.rect(self.screen, WHITE, rect)
def move(self, speed):
self.y += speed
'KEYDOWN'可以检测到关键*不会*下降。你应该检测到'KEYDOWN'和'KEYUP'并跟踪每个键的当前状态(提示,在所有情况下使用'event.key'而不是'keys') –
@NickA我将事件改为'if event.key == pygame.K_q:'等,但我仍然需要每次按下键使其移动。 – kstullich
你需要保持当前的按键状态'q_down = True/False',这取决于它是否被按下/释放,然后在你的游戏循环中你可以做'if q_down:left.move(-30)'(注意我说在你的游戏循环中,不是事件处理循环) –