错误开始新的活动

在我的应用程序我m显示列表中的Tabview，在一个选项卡时，我试图启动一个新的活动onclick列表视图触摸事件。我想在网页视图中开始一项新活动。错误开始新的活动

showNewsListView.setAdapter(listAdapter); 
showNewsListView.setOnItemClickListener(new OnItemClickListener(){ 
    public void onItemClick(AdapterView<?> arg0, View arg1, int position, 
     long arg3) { 
      Log.v("status ","tab on position"+position); 
      Intent myIntent = new Intent(BizTab.this, MainView.class); 
      startActivity(myIntent); 

      } 
      }); 

getUrlData(baseUrl); 

}

，如果我跑这么多的代码的应用程序崩溃，所以我刚刚找到自己的解决方案，我应该在asyncrouniously开始一个新的活动所以现在即时通讯做这个

showNewsListView.setAdapter(listAdapter); 
    showNewsListView.setOnItemClickListener(new OnItemClickListener(){ 
    public void onItemClick(AdapterView arg0, View arg1, int position, long arg3) { Log.v("status ","tab on position"+position); 

     new ShowFullNews().execute(); 
     } 
     }); 
getUrlData(baseUrl); 

}` 

`showNewsListView.setAdapter(listAdapter); 
showNewsListView.setOnItemClickListener(new OnItemClickListener(){ 
    public void onItemClick(AdapterView<?> arg0, View arg1, int position, 
     long arg3) { 
      Log.v("status ","tab on position"+position); 

     new ShowFullNews().execute(); 
     } 
     }); 
getUrlData(baseUrl); 

}`

然后还我的代码崩溃和不给错误只是给这两个警告

如果我在两个地方开始一个新的活动onTouch和后执行然后我的代码是woking，但在这里它首先显示屏幕，然后它自动去刷新屏幕，这不看起来不错。所以如何避免它。请帮我和plese忽略语法错误我的工作代码是

public void onItemClick(AdapterView<?> arg0, View arg1, int position, 
     long arg3) { 
      Log.v("status ","tab on position"+position); 

      //set bundle to send data into other activity 
      b.putInt("total", 10); 
      b.putInt("position",position); 
      b.putStringArray("allurls", allsNewsUrls); 
      b.putString("returnname", "BizTab"); 
      b.putString("footertext","Biz"); 
      b.putInt("tabid", 3); 

      Intent myIntent = new Intent(BizTab.this, MainView.class); 
      myIntent.putExtras(b); 
      startActivity(myIntent); 
      new ShowFullNews().execute(); 
     } 
     }); 

protected void onPostExecute(Long result) { try { 
    Intent myIntent2 = new Intent(BizTab.this, MainView.class); 

startActivity(myIntent2); 


} catch (Exception e) { 
Log.v("error","error in starting new activity"); 
e.printStackTrace(); 
} 

    }`

日志生成和我的应用程序正在自动关闭。

12-07 11:55:18.684: WARN/InputManagerService(72): Window already focused, ignoring focus gain of: [email protected] 
12-07 11:55:20.792: VERBOSE/status(419): tab on position0 
12-07 11:55:20.814: INFO/ActivityManager(72): Starting activity: Intent { cmp=org.nuvus/.MainView (has extras) } 
12-07 11:55:20.872: DEBUG/PhoneWindow(419): couldn't save which view has focus because the focused view [email protected] has no id. 
12-07 11:55:21.023: VERBOSE/status(419): mainView oncreate called 
12-07 11:55:21.452: VERBOSE/status(419): onStartcalled 
12-07 11:55:21.962: INFO/ActivityManager(72): Displayed activity org.nuvus/.MainView: 1072 ms (total 1072 ms) 
12-07 11:55:22.082: INFO/AndroidRuntime(419): AndroidRuntime onExit calling exit(0) 
12-07 11:55:22.173: INFO/ActivityManager(72): Process org.nuvus (pid 419) has died. 
12-07 11:55:22.183: INFO/WindowManager(72): WIN DEATH: Window{43fe6f30 org.nuvus/org.nuvus.Main paused=true} 
12-07 11:55:22.202: INFO/WindowManager(72): WIN DEATH: Window{440f9620 org.nuvus/org.nuvus.MainView paused=false} 
12-07 11:55:22.283: INFO/UsageStats(72): Unexpected resume of com.android.launcher while already resumed in org.nuvus 
12-07 11:55:22.303: WARN/InputManagerService(72): Got RemoteException sending setActive(false) notification to pid 419 uid 10032

请帮我...

来源

2010-12-07 neeraj

你有没有解决这个问题？ – coder 2011-11-29 16:46:20

相反的：

Intent myIntent = new Intent(BizTab.this, MainView.class); 
myIntent.putExtras(b); 
startActivity(myIntent);

尝试用：

Intent myIntent = new Intent(getBaseContext(), BizTab.this); <!-- or MainView.class--> 
myIntent.putExtras(b); 
myIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK); 
startActivity(myIntent);

来源

2010-12-07 14:26:00 Tobia

仍然是同样的问题 – neeraj 2010-12-08 06:03:06

错误开始新的活动

回答

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