3
可以说我有类似的代码如下:Python的大熊猫删除UserWarning,有效地循环
import pandas as pd
df=pd.DataFrame({'Name': [ 'Jay Leno', 'JayLin', 'Jay-Jameson', 'LinLeno', 'Lin Jameson', 'Python Leno', 'Python Lin', 'Python Jameson', 'Lin Jay', 'Python Monte'],
'Class': ['Rat','L','H','L','L','H', 'H','L','L','Circus']})
df['status']=''
pattern1=['^Jay(\s|-)?(Leno|Lin|Jameson)$','^Python(\s|-)?(Jay|Leno|Lin|Jameson|Monte)$','^Lin(\s|-)?(Leno|Jay|Jameson|Monte)$' ]
pattern2=['^Python(\s|-)?(Jay|Leno|Lin|Jameson|Monte)$' ]
pattern3=['^Lin(\s|-)?(Leno|Jay|Jameson|Monte)$' ]
for i in range(len(pattern1)):
df.loc[df.Name.str.contains(pattern1[i]),'status'] = 'A'
for i in range(len(pattern2)):
df.loc[df.Name.str.contains(pattern2[i]),'status'] = 'B'
for i in range(len(pattern3)):
df.loc[df.Name.str.contains(pattern3[i]),'status'] = 'C'
print (df)
它打印:
C:\Python33\lib\site-packages\pandas\core\strings.py:184: UserWarning: This pattern has match groups. To actually get the groups, use str.extract.
" groups, use str.extract.", UserWarning)
Class Name status
0 Rat Jay Leno A
1 L JayLin A
2 H Jay-Jameson A
3 L LinLeno C
4 L Lin Jameson C
5 H Python Leno B
6 H Python Lin B
7 L Python Jameson B
8 L Lin Jay C
9 Circus Python Monte B
[10 rows x 3 columns]
我的问题是我怎么删除错误和是否有办法用更少的代码更有效地循环?我知道有些东西叫做列表解析,但我对如何使用它们感到困惑。
我知道错误可能
pd.options.mode.chained_assignment = None
我在另一组代码上试过这个,但得到了'错误:没有重复' – ccsv
一个显示这个错误的可运行示例会非常有帮助。 – unutbu
没关系我修复它显然你不能有'(:?i)'它必须是'(?i)' – ccsv