选择匹配ONLY/AND条件的记录在一列

Question

我希望能够选择只有亚洲和白色。例如在下面的表格中，我想要检索记录的唯一人员是PersonId 1和2（Desired Result）。

表：

所需的结果：

Answer 1

有，你可以得到结果的几种方法。

使用HAVING子句与聚合函数：

select personid, race 
from yourtable 
where personid in 
    (select personid 
    from yourtable 
    group by personid 
    having 
     sum(case when race = 'white' then 1 else 0 end) > 0 
     and sum(case when race = 'asian' then 1 else 0 end) > 0 
     and sum(case when race not in('asian', 'white') then 1 else 0 end) = 0); 

见SQL Fiddle with Demo

或者您也可以在HAVING子句中使用count(distinct race)：

;with cte as 
(
    select personid 
    from yourtable 
    where race in ('white', 'asian') 
    and personid not in (select personid 
         from yourtable 
         where race not in ('white', 'asian')) 
    group by personid 
    having count(distinct race) = 2 
) 
select personid, race 
from yourtable 
where personid in (select personid 
        from cte); 

见SQL Fiddle with Demo

Answer 2

这应该做

select * from table where personID in (
select personID from table 
group by personID having count(distinct race) = 2 and min(race) = 'Asian' 
and max(race) = 'White') 

Answer 3

非常天真，但应该工作。

select * from yourtable t1 join yourtable t2 on t1.id = t2.id where ((t1.race = 'Asian' and t2.race = 'White') OR (t1.race = 'White' and t2.race = 'Asian')) and t1.id not in (select id from yourtable where race not in ('Asian','white'));