我尝试使用此代码,但给我一个错误:常量100000000000000000000000溢出int64Golang溢出int64
我该如何解决这个问题?
// Initialise big numbers with small numbers
count, one := big.NewInt(100000000000000000000000), big.NewInt(1)
我尝试使用此代码,但给我一个错误:常量100000000000000000000000溢出int64Golang溢出int64
我该如何解决这个问题?
// Initialise big numbers with small numbers
count, one := big.NewInt(100000000000000000000000), big.NewInt(1)
例如这样:
count,one := new(big.Int), big.NewInt(1)
count.SetString("100000000000000000000000",10)
它不会因为引擎盖下工作,big.NewInt实际上是分配一个Int64。你想分配给big.NewInt的数字需要多于64位才能存在,所以它失败了。
但是,如果您想在MaxInt64下面添加两个大数字,那么您可以做到这一点!即使总和大于MaxInt64。下面是一个例子,我只是写了(http://play.golang.org/p/Jv52bMLP_B):
func main() {
count := big.NewInt(0);
count.Add(count, big.NewInt(5000000000000000000));
count.Add(count, big.NewInt(5000000000000000000));
//9223372036854775807 is the max value represented by int64: 2^63 - 1
fmt.Printf("count: %v\nmax int64: 9223372036854775807\n", count);
}
,这导致:
count: 10000000000000000000
max int64: 9223372036854775807
现在,如果你还是好奇NewInt引擎盖下是如何工作的,这里是功能您正在使用,从Go的资料为准,:
// NewInt allocates and returns a new Int set to x.
func NewInt(x int64) *Int {
return new(Int).SetInt64(x)
}
来源: