SQL数据透视表总计

Question

在我试图行和列总计添加到该数据透视表

 create table test4(city nvarchar(10), race nvarchar(30), sex nvarchar(10), age int) 
      insert into test4 values ('Austin', 'African-American', 'male', 21) 
      insert into test4 values ('Austin', 'Asian', 'female', 22) 
      insert into test4 values ('Austin', 'Caucasian', 'male', 23) 
      insert into test4 values ('Austin', 'Hispanic', 'female', 24) 
      insert into test4 values ('Austin', 'African-American', 'Unknown', 25) 
      insert into test4 values ('Austin', 'Asian', 'male', 26) 
      insert into test4 values ('Austin', 'Caucasian', 'female', 27) 
      insert into test4 values ('Austin', 'Hispanic', 'Unknown', 28) 
      insert into test4 values ('Austin', 'Asian', 'male', 29) 
      insert into test4 values ('Austin', 'Caucasian', 'female', 31) 
      insert into test4 values ('Dallas', 'Hispanic', 'Unknown', 32) 
      insert into test4 values ('Dallas', 'African-American', 'male', 33) 
      insert into test4 values ('Dallas', 'Asian', 'female', 34) 
      insert into test4 values ('Dallas', 'Caucasian', 'Unknown', 35) 
      insert into test4 values ('Dallas', 'Hispanic', 'male', 500) 
      insert into test4 values ('Dallas', 'African-American', 'female', 36) 
      insert into test4 values ('Dallas', 'Asian', 'Unknown', 37) 
      insert into test4 values ('Dallas', 'Caucasian', 'male', 38) 
      insert into test4 values ('Dallas', 'Hispanic', 'female', 39) 
      insert into test4 values ('Dallas', 'African-American', 'Unknown', 41) 
      insert into test4 values ('Houston', 'Asian', 'male', 42) 
      insert into test4 values ('Houston', 'Caucasian', 'female', 43) 
      insert into test4 values ('Houston', 'Hispanic', 'Unknown', 44) 
      insert into test4 values ('Houston', 'African-American', 'male', 45) 
      insert into test4 values ('Houston', 'Asian', 'female', 46) 
      insert into test4 values ('Houston', 'Caucasian', 'Unknown', 47) 
      insert into test4 values ('Houston', 'Hispanic', 'male', 48) 
      insert into test4 values ('Houston', 'African-American', 'female', 49) 
      insert into test4 values ('Houston', 'Asian', 'Unknown', 51) 
      insert into test4 values ('Houston', 'Caucasian', 'male', 52); 

      WITH T AS (
      SELECT 
        A.city as city, A.sex as sex, 
        CASE 
         WHEN A.age BETWEEN 20 AND 30 THEN '20-30_' + race 
         WHEN A.age BETWEEN 31 AND 40 THEN '31-40_' + race 
         WHEN A.age BETWEEN 41 AND 50 THEN '41-50_' + race 
        END AS age_range_race 
      FROM test4 AS A 
      ) 
      SELECT * 
      FROM T 
      PIVOT(COUNT(age_range_race) FOR age_range_race 
       IN(
        [20-30_African-American], 
        [20-30_Asian], 
        [20-30_Caucasian], 
        [20-30_Hispanic], 
        [31-40_African-American], 
        [31-40_Asian], 
        [31-40_Caucasian], 
        [31-40_Hispanic], 
        [41-50_African-American], 
        [41-50_Asian], 
        [41-50_Caucasian], 
        [41-50_Hispanic] 
       ) 
      ) AS P 

我想实现这个结果

1 http://img853.imageshack.us/img853/8112/sqltotal.jpg

唯一的例子我可以在Google上找到为SQL 2000编写的存储过程。请帮忙！在此先感谢

Answer 1

在这里，你试试。

WITH T AS (
      SELECT 
        A.city as city, A.sex as sex, 
        CASE 
         WHEN A.age BETWEEN 20 AND 30 THEN '20-30_' + race 
         WHEN A.age BETWEEN 31 AND 40 THEN '31-40_' + race 
         WHEN A.age BETWEEN 41 AND 50 THEN '41-50_' + race 
        END AS age_range_race 
      FROM #test4 AS A 
      ) 


SELECT *, ([20-30_African-American] + [20-30_Asian] + [20-30_Caucasian]+ [20-30_Hispanic]+ [31-40_African-American]+ [31-40_Asian]+ [31-40_Caucasian]+ [31-40_Hispanic]+[41-50_African-American]+ [41-50_Asian]+ [41-50_Caucasian]+ [41-50_Hispanic]) Total 
into #tmp_result 
FROM T 
PIVOT(COUNT(age_range_race) FOR age_range_race 
    IN(
     [20-30_African-American], 
     [20-30_Asian], 
     [20-30_Caucasian], 
     [20-30_Hispanic], 
     [31-40_African-American], 
     [31-40_Asian], 
     [31-40_Caucasian], 
     [31-40_Hispanic], 
     [41-50_African-American], 
     [41-50_Asian], 
     [41-50_Caucasian], 
     [41-50_Hispanic] 
    ) 
) AS P 

select * 
from #tmp_result 
union all 
select 'Grand Total','',SUM([20-30_African-American]), SUM([20-30_Asian]), SUM([20-30_Caucasian]), SUM([20-30_Hispanic]),SUM([31-40_African-American]), SUM([31-40_Asian]), SUM([31-40_Caucasian]), SUM([31-40_Hispanic]),SUM([41-50_African-American]), SUM([41-50_Asian]), SUM([41-50_Caucasian]),SUM([41-50_Hispanic]), sum(Total) 
from #tmp_result 

Answer 2

请尝试如下..

WITH T AS (
      SELECT 
        A.city as city, A.sex as sex, 
        CASE 
         WHEN A.age BETWEEN 20 AND 30 THEN '20-30_' + race 
         WHEN A.age BETWEEN 31 AND 40 THEN '31-40_' + race 
         WHEN A.age BETWEEN 41 AND 50 THEN '41-50_' + race 
        END AS age_range_race 
      FROM #test4 AS A 
      ) 


SELECT *, ([20-30_African-American] + [20-30_Asian] + [20-30_Caucasian]+ [20-30_Hispanic]+ [31-40_African-American]+ [31-40_Asian]+ [31-40_Caucasian]+ [31-40_Hispanic]+[41-50_African-American]+ [41-50_Asian]+ [41-50_Caucasian]+ [41-50_Hispanic]) Total 
FROM T 
PIVOT(COUNT(age_range_race) FOR age_range_race 
    IN(
     [20-30_African-American], 
     [20-30_Asian], 
     [20-30_Caucasian], 
     [20-30_Hispanic], 
     [31-40_African-American], 
     [31-40_Asian], 
     [31-40_Caucasian], 
     [31-40_Hispanic], 
     [41-50_African-American], 
     [41-50_Asian], 
     [41-50_Caucasian], 
     [41-50_Hispanic] 
    ) 
) AS P