如何在动态数据透视中总计多于1 sql

Question

我试图用动态数据透视中的2个coulin创建一个总数为2的子查询。

我有表&这样的查询

CREATE TABLE #SampleData 
 
(
 
    Class varchar(10), 
 
    Name varchar(10), 
 
    Location varchar(10), 
 
    Item varchar(10), 
 
    temp varchar (10) 
 
) 
 

 
INSERT INTO #SampleData 
 
VALUES 
 
('abc', 'Ron', 'A', 'Pencil', '12345'), 
 
('abc', 'Ron', 'A', 'Pen', '2345'), 
 
('abc', 'Tom', 'C', 'Pencil', '34343'), 
 
('abc', 'Tom', 'D', 'Pencil', '252525'), 
 
('def', 'Ron', 'E', 'Pen', '35345'), 
 
('def', 'Tom', 'F', 'Pencil', '87878'), 
 
('def', 'Tom', 'G', 'Pen', '9876'), 
 
('ghi', 'Ron', 'H', 'Pen', '09090'), 
 
('ghi', 'Ron', 'I', 'Pen', '40404'), 
 
('ghi', 'Tom', 'J', 'Pencil', '144442345'), 
 
('ghi', 'Tom', 'K', 'Pencil', '4444333') 
 

 

 
DECLARE @Pivot_Columns AS VARCHAR(MAX), 
 
     @select_Columns VARCHAR(max) 
 

 
SELECT @Pivot_Columns = Stuff((SELECT DISTINCT ',' + Quotename(item) FROM #SampleData FOR xml path('')), 1, 1, '') 
 
SELECT @select_Columns = Stuff((SELECT DISTINCT ',Sum(' + Quotename(item) + ') as '+Quotename(item) FROM #SampleData FOR xml path('')), 1, 1, '') 
 

 
DECLARE @SQL AS VARCHAR(MAX) 
 

 
SET @SQL = 'SELECT case when grouping(name) = 1 and grouping(class) = 0 then ''Total''+ '' '' + class 
 
when grouping(name) = 1 and grouping(class) = 1 then ''Total'' 
 
else class end class, name, location, temp,' 
 
      + @select_Columns + ' 
 
FROM 
 
(
 
    SELECT class, name, location, item, temp 
 
    FROM #SampleData 
 

 
) as PivotData 
 
PIVOT 
 
(
 
    count(item) 
 
    for item IN (' 
 
      + @Pivot_Columns + ') 
 
) AS PivotResult 
 
group by class, name, location, temp with rollup 
 
' 
 

 
EXEC(@SQL)

，以及如何创建这样的数据吗？

我只是想告诉从名称大部基于类&大部类，但在我的第一成像有基于温度子总。如果我更改'按类别分组，名称与汇总'有显示错误..

感谢任何帮助，谢谢。

Answer 1

我想你可以试试这个（我只是回顾第一种情况下，增加了对名称的CASE和添加具有条件）：

SET @SQL = 'SELECT 
        case when grouping(name) = 1 and grouping(class) = 0 then ''TOTAL ''+ '' '' + class 
         when grouping(name) = 1 and grouping(class) = 1 then ''TOTAL ''      
         else class end class 
      , case when grouping(location)=1 AND grouping(temp)=1 THEN ''TOTAL ''+name 
         else name end name, location, temp,' 
      + @select_Columns + ' 
FROM 
(
    SELECT class, name, location, item, temp 
    FROM #SampleData 

) as PivotData 
PIVOT 
(
    count(item) 
    for item IN (' 
      + @Pivot_Columns + ') 
) AS PivotResult 
group by class, name, location, temp with ROLLUP 
HAVING (grouping(location)=1 AND grouping(temp)=1) OR (grouping(location)=0 AND grouping(temp)=0 AND grouping(name)=0 AND grouping(class)=0) 
' 

更新：

您可以使用GROUPING SETS，获得相同的结果（避免在我以前的查询中使用HAVING条件）：

SET @SQL = 'SELECT 
        case when grouping(name) = 1 and grouping(class) = 0 then ''TOTAL ''+ '' '' + class 
         when grouping(name) = 1 and grouping(class) = 1 then ''TOTAL ''      
         else class end class 
      , case when grouping(location)=1 AND grouping(temp)=1 THEN ''TOTAL ''+name 
         else name end name, location, temp,' 
      + @select_Columns + ' 
FROM 
(
    SELECT class, name, location, item, temp 
    FROM #SampleData 

) as PivotData 
PIVOT 
(
    count(item) 
    for item IN (' 
      + @Pivot_Columns + ') 
) AS PivotResult 
group by GROUPING SETS ((class,name), (class), (class, name, location, temp),()) 

' 

输出：

+------------+-----------+----------+-----------+-----+--------+ 
| class | name | location | temp | Pen | Pencil | 
+------------+-----------+----------+-----------+-----+--------+ 
| abc  | Ron  | A  | 12345  | 0 |  1 | 
| abc  | Ron  | A  | 2345  | 1 |  0 | 
| abc  | TOTAL Ron | NULL  | NULL  | 1 |  1 | 
| abc  | Tom  | C  | 34343  | 0 |  1 | 
| abc  | Tom  | D  | 252525 | 0 |  1 | 
| abc  | TOTAL Tom | NULL  | NULL  | 0 |  2 | 
| TOTAL abc | NULL  | NULL  | NULL  | 1 |  3 | 
| def  | Ron  | E  | 35345  | 1 |  0 | 
| def  | TOTAL Ron | NULL  | NULL  | 1 |  0 | 
| def  | Tom  | F  | 87878  | 0 |  1 | 
| def  | Tom  | G  | 9876  | 1 |  0 | 
| def  | TOTAL Tom | NULL  | NULL  | 1 |  1 | 
| TOTAL def | NULL  | NULL  | NULL  | 2 |  1 | 
| ghi  | Ron  | H  | 09090  | 1 |  0 | 
| ghi  | Ron  | I  | 40404  | 1 |  0 | 
| ghi  | TOTAL Ron | NULL  | NULL  | 2 |  0 | 
| ghi  | Tom  | J  | 144442345 | 0 |  1 | 
| ghi  | Tom  | K  | 4444333 | 0 |  1 | 
| ghi  | TOTAL Tom | NULL  | NULL  | 0 |  2 | 
| TOTAL ghi | NULL  | NULL  | NULL  | 2 |  2 | 
| TOTAL  | NULL  | NULL  | NULL  | 5 |  6 | 
+------------+-----------+----------+-----------+-----+--------+ 

Answer 2

您可能会感兴趣this link对您有所帮助。

或者，这里是另一种解决方案：

SELECT SUM(CASE WHEN Code = '01' THEN Value1 ELSE 0 END) AS Value1_01 
    ,SUM(CASE WHEN Code = '02' THEN Value1 ELSE 0 END) AS Value1_02 
    ,SUM(CASE WHEN Code = '01' THEN Value2 ELSE 0 END) AS Value2_01 
    ,SUM(CASE WHEN Code = '02' THEN Value2 ELSE 0 END) AS Value2_02 
FROM TableName