如何在Android应用程序中访问下载的audios文件夹

Question

我正在开发一个简单的音频流android应用程序。在从网址播放音频时，应用程序还可以选择下载文件。正在下载音频文件内部存储/声音文件夹。如何在我的应用程序中显示该文件夹的所有已下载的音频？我想要访问声音文件夹中的所有音频并在我的应用程序中显示，以便用户无需手动搜索文件。请指导。谢谢！

Answer 1

String path = Environment.getExternalStorageDirectory().toString()+"/voices"; 
Log.d("Files", "Path: " + path); 
File directory = new File(path); 
File[] files = directory.listFiles(); 
Log.d("Files", "Size: "+ files.length); 
for (int i = 0; i < files.length; i++) 
{ 
    Log.d("Files", "FileName:" + files[i].getName()); 
} 

这样你会得到存储在voices目录到files阵列中的所有文件。

Answer 2

我这样做是使用下面的代码：

private ListView mainListView ; 
private ArrayAdapter<String> listAdapter ; 
private MediaPlayer mp = new MediaPlayer(); 
private List<String> ListOfFiles = new ArrayList<String>(); 
String path = Environment.getExternalStorageDirectory().toString()+"/voices"; 

@Override 
protected void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    setContentView(R.layout.activity_main); 


    // Find the ListView resource. 
    mainListView = (ListView) findViewById(R.id.mainListView); 


    Log.d("Files", "Path: " + path); 
    File directory = new File(path); 
    File[] files = directory.listFiles(); 
    Log.d("Files", "Size: "+ files.length); 
    for (int i = 0; i < files.length; i++) 
    { 
     Log.d("Files", "FileName:" + files[i].getName()); 
    } 

    for (int i = 0; i < files.length; i++) { 
     ListOfFiles.add(files[i].getName()); 
    } 


    listAdapter = new ArrayAdapter<String>(this, R.layout.row_layout, ListOfFiles); 
    mainListView.setAdapter(listAdapter); 


    mainListView.setOnItemClickListener(new AdapterView.OnItemClickListener() { 
     @Override 
     public void onItemClick(AdapterView<?> parent, View view, 
           int position, long id) { 
      playSong(path +"/"+ ListOfFiles.get(position)); 

      Log.d("Path",path + ListOfFiles.get(position)); 
     } 
    }); 
} 

private void playSong(String songPath) { 
    try { 
     mp.reset(); 
     mp.setDataSource(songPath); 
     mp.prepare(); 
     mp.start(); 
    } catch (IOException e) { 
     Log.v(getString(R.string.app_name), e.getMessage()); 
    } 
}