pythonchallenge.com 4在红宝石溶液

Question

http://www.pythonchallenge.com/pc/def/linkedlist.php是否有比下面的红宝石代码更好的/可选的/更易读的解决方案？ 我能理解它，但它只是似乎并没有我很清楚...

#!/usr/bin/env ruby -w 
# encoding: utf-8 

require 'net/http' 

Net::HTTP.start 'www.pythonchallenge.com' do |http| 
    nothing = 12345 

    nothing = case http.get("/pc/def/linkedlist.php?nothing=#{nothing}").body 
    when /(\d+)$/ then $1.to_i 
    when /by two/ then nothing/2 
    when /\.html/ then puts $` 
    end while nothing 
end 

Answer 1

这是好的，但是让我们试着让它多一点可读性：

#!/usr/bin/env ruby -w 
# encoding: utf-8 

require 'net/http' 

Net::HTTP.start 'www.pythonchallenge.com' do |http| 
    next_one = 12345 

    while next_one 
    response = http.get("/pc/def/linkedlist.php?nothing=#{next_one}").body 

    case response 
     when /Divide by two and keep going./ then 
     next_one = next_one/2 
     when /and the next nothing is (\d+)/ then 
     next_one = $1.to_i 
     else 
     puts "Solution url: www.pythonchallenge.com/pc/def/linkedlist.php?nothing=#{next_one}" 
     next_one = false 
    end 
    end 

end