如果我有一个形状像这样的Python列表:重塑一个Python列表,同时保持顺序
T = [
['07,07,2012 22:10', ['people','drama','melody','bun']],
['08,07,2012 21:04', ['queen','group']],
['08,07,2012 21:23', ['printing','market','shopping']],
['08,07,2012 21:04', ['people','bun']],
['08,11,2012 11:14', ['kangaroo']]
]
我需要的是这个列表转换成这种格式:
T =[
['07,07,2012 22:10', 'people'],
['07,07,2012 22:10', 'drama'],
['07,07,2012 22:10', 'melody'],
['07,07,2012 22:10', 'bun'],
['08,07,2012 21:04', 'queen'],
['08,07,2012 21:04', 'group'],
['08,07,2012 21:23', 'printing'],
['08,07,2012 21:23', 'market'],
['08,07,2012 21:23', 'shopping'],
['08,07,2012 21:04', 'people'],
['08,07,2012 21:04', 'bun'],
[''08,11,2012 11:14'', 'kangaroo']
]
即对于第一个子元素的长度大于1(在原始列表T中)的每个元素,分割第一个子元素(a[1] for a in T if len(a[1] > 1)
)并将其作为具有相同时间戳的另一个列表追加。也许我的话缺乏解释,但上述样本无疑解释了我需要做的事情。任何帮助,将不胜感激。
或者使用一个列表而不是一个元组来获得OP所要求的内容(尽管应该不重要)。 –
谢谢@ flornquake..you艺术家总结了这一切。非常感谢 :-) – khan