我不断收到此错误的验证码不兼容的类型为const char的分配到的std :: string

Question

if(gamble == "You Get A Raise"){ 
      int raise[] {1,2,3,4,5,6,7,8,9,10} 
      cout << "You get a "  raise[rand()%10] << " $ Raise" << endl; 
      salary = salary + raise; 
} 

我试着做挑出一批1-10的节目，然后补充说，以当前的薪水

Answer 1

你忘了<<？

试试这个：

int raise[] = {1,2,3,4,5,6,7,8,9,10}; 
int raise_value = rand()%10; 
cout << "You get a " << raise[raise_value] << " $ Raise" << endl; 
salary += raise[raise_value]; 

你的字符串gamble必须std::string太：

std::string gamble = "You Get A Raise"; 

---

这是一个完整的例子：

int salary = 1000; 
std::string gamble = "You Get A Raise"; 
int raise[] = {1,2,3,4,5,6,7,8,9,10}; 

if (std::strcmp(gamble.c_str(),"You Get A Raise") == 0) { 
// or 
// if (gamble.compare("You Get A Raise") == 0) { 

    int raise_value = rand()%10; 
    cout << "You get a " << raise[raise_value] << " $ Raise" << endl; 
    salary += raise[raise_value]; 
    cout << "New salary is $" << salary << endl; 
} 

Answer 2

你居然要STOR e加薪指数：rand()%10为了显示，然后将同样的加薪应用于薪水。

int raise[] {1,2,3,4,5,6,7,8,9,10}; 
int raiseIdx = rand()%10; 
cout << "You get a " << raise[raiseIdx] << " $ Raise" << endl; 
salary = salary + raise[raiseIdx]; 

你gamble变量应该是一个std::string：

std::string gamble = "You Get A Raise";