2015-12-23 98 views
0

我希望能创建一个函数来为绘图设置x轴限制。这里是什么,是工作目前:将绘图传递给函数Matplotlib Python

import matplotlib.pyplot as plt 

def scatter_plot(df, user_conditions): 
    data_to_plot = user_conditions['data_to_plot'] 
    title = data_to_plot.replace("_", " ").title() 
    df1 = df[['time',data_to_plot]] 
    df1 = index_dataframe_time(df1) 
    plt.scatter(df1.index.to_pydatetime(), df1[data_to_plot]) 
    min = df1.index.min() 
    max = df1.index.max() 
    plt.xlim(min, max) 
    plt.title('Hour of Day vs '+title, fontsize=14) 
    plt.show() 

这是我所期待的:

def scatter_plot(df, user_conditions): 
    data_to_plot = user_conditions['data_to_plot'] 
    title = data_to_plot.replace("_", " ").title() 
    print title 
    df1 = df[['time',data_to_plot]] 
    df1 = index_dataframe_time(df1) 
    plot = plt.scatter(df1.index.to_pydatetime(), df1[data_to_plot]) 
    plot = set_limits(df1, plot) 
    plot.title('Hour of Day vs '+title, fontsize=14) 
    plot.show() 

def set_limits(df, plot): 
    min = df.index.min() 
    max = df.index.max() 
    plot.xlim(min, max) 
    return plot 

然而,在set_limitsplot.xlim(min,max)问题,

> Traceback (most recent call last): 
File 
> "C:/Users/Application/main.py", line 115, in <module> 
>  
main() 
> 
> File "C:/Users/Application/main.py", line 
> 106, 
> in main 
>  plot_configuration(df, user_conditions) File "C:/Users/Application/main.py", line 111, 
> in plot_configuration 
>  scatter_plot(df, user_conditions) 
File "C:/Users/Application/main.py", line 76, 
> in scatter_plot 
>  plot = set_limits(df1, plot) File "C:/Users/Application/main.py", line 83, 
> in set_limits 
>  plot.xlim(min, max) AttributeError: 'PathCollection' object has no attribute 'xlim' 

如何可以修改set_limits来解决这个问题吗?

+0

你是如何导入'matplotlib'的?例如'plt'从哪里来? – mgilson

+0

@mgilson对不起,这个问题现在已经修复,以反映 – Withoutahold

+1

问题是'pyplot'是一个有状态的模块,它对于习惯于matlab的人来说是很方便的。特别的,有状态是为什么'plt.set_xlim'工作的原因 - 'pyplot'对你当前使用的图形(和坐标轴)有一个引用。如果你想自己处理这些图,这不起作用(好),你需要使用'matplotlib.figure'提供的面向对象的接口。 [参考](http://stackoverflow.com/a/5450333/748858)。我想你可以使用'pyplot.gcf()'来获得当前的数字...... – mgilson

回答

0

你可能想要做这样的事情:

import matplotlib.pyplot as plt 

def scatter_plot(ax, df, user_conditions): 
    """ 
    Parameters 
    ---------- 
    ax : matplotlib.axes.Axes 
     The axes to put the data on 
    df : pd.DataFrame 
     The data 
    user_conditions : dict (?) 
     bucket of user input to control plotting? 
    """ 
    data_to_plot = user_conditions['data_to_plot'] 
    title = data_to_plot.replace("_", " ").title() 
    print(title) 
    df1 = df[['time',data_to_plot]] 
    df1 = index_dataframe_time(df1) 
    # sc = ax.scatter(df1.index.to_pydatetime(), df1[data_to_plot]) 
    # only works in 1.5.0+ 
    sc = ax.scatter(df1.index.to_pydatetime(), data_to_plot, 
        data=df) 
    set_limits(df1, ax) 
    ax.set_title('Hour of Day vs '+title, fontsize=14) 

    return sc 

def set_limits(df, ax): 
    min = df.index.min() 
    max = df.index.max() 
    ax.set_xlim(min, max) 


fig, ax = plt.subplots() 
arts = scatter_plot(ax, df, user_conditions) 

,如果你不改变标志的大小或颜色,你最好使用ax.plot(..., linestile='none', marker='o')将呈现更快。在这种情况下(如果你有1.5.0+)

ax.plot(data_to_plot, linestyle='none', marker='o', data=df) 

它应该'做正确的事情'。