0
我有这个剧本与我的数据库是MySQL的无法团结从PHP接收数据
string dataSubmitURL = "http://localhost/HighScore/AddScore.php?";
string dataGetURL = "http://localhost/HighScore/GetScore.php?";
// Use this for initialization
void Start() {
StartCoroutine(GetScores());
}
// Update is called once per frame
void Update() {
}
IEnumerator PostScores(string playerName, int score) {
string submitURL = dataSubmitURL + "name="+ playerName + "&score=" + score;
print(submitURL);
WWW submitData = new WWW(submitURL);
yield return submitData;
if (submitData.error != null)
{
Debug.LogError("Error occur when Submitting data : " + submitData.error);
Debug.LogError("Error occur when Submitting data : " + submitData.text);
Debug.LogError("Error occur when Submitting data : " + submitData.responseHeaders);
//submitData.text
}
else {
print(" Submitted");
}
IEnumerator GetScores() {
WWW getData = new WWW(dataGetURL);
yield return getData;
if (getData.error != null)
{
Debug.LogError("There was an error getting the high score: " + getData.error);
}
else {
print(getData.text);
}
}
}
但问题是我得到
时出错获取互动高分:从服务器空回复
虽然这两个URL
string dataSubmitURL = "http://localhost/HighScore/AddScore.php?";
string dataGetURL = "http://localhost/HighScore/GetScore.php?";
在浏览器中正常工作时,我直接把它。我还在根文件夹中添加了这个crossDomain.xml,以便所有人都可以访问它。我做错了什么。
<?xml version="1.0"?>
<cross-domain-policy>
<allow-access-from domain="*"/>
</cross-domain-policy>