2016-08-19 142 views
2

我得到了两个MYSQL表,我不知道是否有任何聚合函数MYSQL array_agg()从PostgreSQL。MYSQL数组聚合函数像PostgreSQL array_agg

表1性能只有8条 表2记录谁抓住了财产,所以有时可以为同一财产1或N次,我得到这个QRY:

SELECT p.id, pcb.users_admin_id as uid 
FROM properties p 
INNER JOIN prop_captured_by pcb ON p.id = pcb.property_id 
-- GROUP BY p.id 

id uid 
200 1 
200 80 
202 1 
202 80 
211 1 
211 10 
211 81 
215 10 ... 

如果我使用GROUP BY部分我得到:

id uid 
200 1 
202 1 
211 1 
215 10 ... 

丢失users_admin_id的第一个值以外的任何其他数据。我知道我可以通过postgreSQL中的array_agg()函数实现我想要的结果,但我无法弄清楚如何在MYSQL上完成它。

这是我的愿望。结果:

id uid 
200 1,80 //an array, I don't mind about the separator, could be anything. 
202 1,80 
211 1,10,81 
215 10 ... 

我已经试过UNION,GROUP BY,INNER JOIN ...没有运气... 任何指针?

UPDATE

我使用从这个家伙的many to many relations。希望它对别人有用。我需要从第三个表添加用户的名称,所以最终的查询看起来是这样的:

SELECT p.id, group_concat(pcb.users_admin_id) as uid, group_concat(ua.name) as uin 
FROM properties p 
INNER JOIN prop_captured_by pcb ON p.id = pcb.property_id 
INNER JOIN users_admin ua ON ua.id = pcb.users_admin_id 
group by p.id; 

回答

8

你想用GROUP_CONCAT()像介绍JSON_ARRAYAGG()JSON_OBJECTAGG()

SELECT p.id, group_concat(pcb.users_admin_id) as uid 
FROM properties p 
INNER JOIN prop_captured_by pcb 
ON p.id = pcb.property_id 
group by p.id; 
+0

这对我的作品! –

5

我想你想要group_concat()

SELECT p.id, GROUP_CONCAT(pcb.users_admin_id) as uids 
FROM properties p INNER JOIN 
    prop_captured_by pcb 
    ON p.id = pcb.property_id 
GROUP BY p.id; 

这将产生一个逗号分隔的字符串,但与您在MySQL中获得的数组非常接近。

0

MySQL的22年7月5日。既然你想要的用户名,以及,你可以使用后者:

SELECT p.id, JSON_OBJECTAGG(pcb.users_admin_id, ua.name) as uin 
FROM properties p 
INNER JOIN prop_captured_by pcb ON p.id = pcb.property_id 
INNER JOIN users_admin ua ON ua.id = pcb.users_admin_id 
group by p.id; 

DB Fiddle