2014-06-30 123 views
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代码:FloatBuffer抛出异常?我怎样才能解决这个问题?

FloatBuffer buf = BufferTools.reserveData(4); 
float[] fl = new float[]{0.1f, 0.1f, 0.1f, 1.0f}; 
buf.put(fl); 

其中buf.put(fl)是线2039的错误都在谈论:

Exception in thread "main" java.lang.IllegalArgumentException: Number of remaining buffer elements is 0, must be at least 4. Because at most 4 elements can be returned, a buffer with at least 4 elements is required, regardless of actual returned element count 
    at org.lwjgl.BufferChecks.throwBufferSizeException(BufferChecks.java:162) 
    at org.lwjgl.BufferChecks.checkBufferSize(BufferChecks.java:189) 
    at org.lwjgl.BufferChecks.checkBuffer(BufferChecks.java:258) 
    at org.lwjgl.opengl.GL11.glLight(GL11.java:2039) 
    at Joehot200.TerrainDemo.setUpLighting(TerrainDemo.java:1543) 
    at Joehot200.TerrainDemo.enterGameLoop(TerrainDemo.java:1984) 
    at Joehot200.TerrainDemo.startGame(TerrainDemo.java:2109) 
    at Joehot200.Main.main(Main.java:56) 

我在做什么错?我只想拥有一个带有4个元素的FloatBuffer,这样我就可以设置OpenGL环境照明。

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什么是TerrainDemo:2109年,1984年和1543年? – Brian

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因此,您向我们展示的代码来自'org.lwjgl.opengl.GL11',而不是您自己的代码? –

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BufferTools不是'org.lwggl' API。它从何而来? –

回答

1

LWJGL抛出这个错误,它的缓冲区对于请求的操作来说太小。见here

我的猜测是BufferTools.reserveData(4)保留4个字节,而不是4 * sizeof(float)== 16字节。

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