你可以试试这个一个
只需复制并粘贴准备和改变的变量,同样的推移行的基础上,执行上的行
<div class="content-loader">
<?php
require_once 'dbconfig.php';
$stmt1 = $db_con->prepare("SELECT ranks.steamId, ranks.points, ranks.lastDisplayName, ranks.lastUpdated, ranksrussia2.points AS points2, uconomy.balance FROM ranks INNER JOIN ranksrussia2 ON ranks.steamId = ranksrussia2.steamId LEFT JOIN uconomy ON ranks.steamId = uconomy.steamId WHERE ranks.steamId = ?");
$stmt2 = $db_con->prepare("SELECT ranks.steamId, ranks.points, ranks.lastDisplayName, ranks.lastUpdated, ranksrussia2.points AS points2, uconomy.balance FROM ranks INNER JOIN ranksrussia2 ON ranks.steamId = ranksrussia2.steamId LEFT JOIN uconomy ON ranks.steamId = uconomy.steamId WHERE ranks.steamId = ?");
$stmt3 = $db_con->prepare("SELECT ranks.steamId, ranks.points, ranks.lastDisplayName, ranks.lastUpdated, ranksrussia2.points AS points2, uconomy.balance FROM ranks INNER JOIN ranksrussia2 ON ranks.steamId = ranksrussia2.steamId LEFT JOIN uconomy ON ranks.steamId = uconomy.steamId WHERE ranks.steamId = ?");
$stmt4 = $db_con->prepare("SELECT ranks.steamId, ranks.points, ranks.lastDisplayName, ranks.lastUpdated, ranksrussia2.points AS points2, uconomy.balance FROM ranks INNER JOIN ranksrussia2 ON ranks.steamId = ranksrussia2.steamId LEFT JOIN uconomy ON ranks.steamId = uconomy.steamId WHERE ranks.steamId = ?");
$stmt5 = $db_con->prepare("SELECT ranks.steamId, ranks.points, ranks.lastDisplayName, ranks.lastUpdated, ranksrussia2.points AS points2, uconomy.balance FROM ranks INNER JOIN ranksrussia2 ON ranks.steamId = ranksrussia2.steamId LEFT JOIN uconomy ON ranks.steamId = uconomy.steamId WHERE ranks.steamId = ?");
$stmt1->execute(array($steamprofile['steamid']));
$stmt2->execute(array($steamprofile['steamid']));
$stmt3->execute(array($steamprofile['steamid']));
$stmt4->execute(array($steamprofile['steamid']));
$stmt5->execute(array($steamprofile['steamid']));
?>
<table cellspacing="0" width="100%" id="rank2" class="table table-striped table-hover table-responsive">
<thead>
<tr>
<td>Nick</td>
<?php
while($row = $stmt1->fetch(PDO::FETCH_ASSOC))
{
echo "<td>". $row['lastDisplayName']."</td>";
}
?>
</tr>
<tr>
<td>Kredity</td>
<?php
while($row = $stmt2->fetch(PDO::FETCH_ASSOC))
{
echo "<td>". $row['balance'] ."</td>";
}
?>
</tr>
<tr>
<td>Body1</td>
<?php
while($row = $stmt3->fetch(PDO::FETCH_ASSOC))
{
echo "<td>". $row['points'] ."</td>";
}
?>
</tr>
<tr>
<td>Body2</td>
<?php
while($row = $stmt4->fetch(PDO::FETCH_ASSOC))
{
echo "<td>". $row['points2'] ."</td>";
}
?>
</tr>
<tr>
<td>Cas</td>
<?php
while($row = $stmt5->fetch(PDO::FETCH_ASSOC))
{
echo "<td>". $row['points2'] ."</td>";
}
?>
</tr>
<tr>
<td>Online</td>
</tr>
</thead>
<tbody>
</tbody>
</table>
</div>
您不清楚您实际询问的内容。在这里,你的意思是什么_exactly_是什么意思?你有一张有几列的桌子。精细。显然你会尝试将这些列输出到一个html表格中。 “垂直”和“水平”在哪里起作用? – arkascha
@arkascha OP需要垂直列出“th”,我想。所以,每个'tr'都会有'td's值为一个类型 –
@u_mulder可能是,可能是,但问题是模糊的... – arkascha