如何在Python中打印正数的数字的符号+

Question

是否有更好的方法在正数上打印数字的正号？

integer1 = 10 
integer2 = 5 
sign = '' 
total = integer1-integer2 
if total > 0: sign = '+' 
print 'Total:'+sign+str(total) 

0应该返回0没有+。

Answer 1

>>> print "%+d" % (-1) 
-1 
>>> 
>>> print "%+d" % (1) 
+1 
>>> print "%+d" % (0) 
+0 
>>> 

这里是the documentation。

** **更新如果因任何原因，你不能使用%运营商，你并不需要的功能：

>>> total = -10; print "Total:" + ["", "+"][total > 0] + str(total) 
Total:-10 
>>> total = 0; print "Total:" + ["", "+"][total > 0] + str(total) 
Total:0 
>>> total = 10; print "Total:" + ["", "+"][total > 0] + str(total) 
Total:+10 
>>> 

Answer 2

使用new string format

>>> '{0:+} number'.format(1) 
'+1 number' 
>>> '{0:+} number'.format(-1) 
'-1 number' 
>>> '{0:+} number'.format(-37) 
'-37 number' 
>>> '{0:+} number'.format(37) 
'+37 number' 
# As the questions ask for it, little trick for not printing it on 0 
>>> number = 1 
>>> '{0:{1}} number'.format(number, '+' if number else '') 
'+1 number' 
>>> number = 0 
>>> '{0:{1}} number'.format(number, '+' if number else '') 
'0 number' 

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