我在哪里接收我在android中发送的对象？

Question

我有这个php代码，我不知道我怎么能把所有这些数组发送到代码的末尾，只有一个数组，以便我可以发送这个数组到android？

$username = $_POST["username"]; 
$locations_string = ""; 
$names = array(); 
$response1= array(); 
$response2= array(); 
$user_record = mysql_query("SELECT * FROM users WHERE username='$username'"); 
$value = mysql_fetch_array($user_record); 
$userlocation = $value['location']; 

$query = mysql_query("SELECT * FROM AllFriendsExceptBlocked WHERE username ='$username'  "); 

while($row = mysql_fetch_array($query)){ 
array_push($names , $value["friendname"]); 

echo $row['friendname']. " - ". $row['location']; 
echo "<br />"; 
} 
for($i=0; $i < count($names) ; $i++){ 
$friend = $names[$i]; 
$user_record = mysql_query("SELECT * FROM AllFriendsExceptBlocked WHERE  friendname='$friend' "); 
$value = mysql_fetch_array($user_record); 
$locations_string = $locations_string . "," . $value['location']; 

} 
$response["message"] = "send locations of friends in AllFriendsExceptBlocked"; 
$response1["panicedUserLocation"] = $userlocation; 
$response2["locations"] = $locations_string; 

echo json_encode($response); 
json_encode($response); 
echo json_encode($response2); 
json_encode($response2); 
echo json_encode($response2); 
json_encode($response2); 

现在我怎么能接收到我从Android中发送的PHP响应？

Answer 1

从http调用中获得响应的位置尝试将响应转换为json对象。例。

InputStream JsonStream=responce.getEntity().getContent(); 
BufferedReader reader= new BufferedReader(new InputStreamReader(JsonStream)); 
StringBuilder builder = new StringBuilder(); 
String line; 
while((line=reader.readLine())!=null) 
{ 

    builder.append(line); 
} 
String JSONdata = builder.toString(); 
Log.i("JsonData",JSONdata); 
JSONObject json = new JSONObject(JSONdata);