基于Ajax响应我试图检查或取消选中复选框,我已经尝试过这种方式无法基于Ajax响应设置复选框属性真假
var jsonresponse = {
"packs": [
{
"pac_newflag": "no"
},
{
"pac_newflag": "yes"
}]
}
var html = '';
$(document).ready(function()
{
for (var i = 0; i < jsonresponse.packs.length; i++)
{
var pac_newflag = jsonresponse.packs[i].pac_newflag;
var checkboxchecked = 'false'
if (pac_newflag === 'yes')
{
checkboxchecked = 'true'
}
else
{
checkboxchecked = 'false'
}
html += '<label class="checkbox"><input type="checkbox" value=checkboxchecked /> Featured</label>';
}
$("#testdiv").html(html);
});
,这是我的小提琴
http://jsfiddle.net/cod7ceho/121/
可否请你让我知道如何与这条线做
HTML + = '<标签类= “复选框”>主要'; –