集团按分支发行

Question

我有3个表agencytbl，branchtbl和tourtbl。我试图计算与分支机构相关的总分行数和与分行相关的总体行程数。这是我的查询：

SELECT dbo.AgencyTbl.AgencyName AS [LIST OF EACH AGENCY], 
(select COUNT(*) from BranchTbl where BranchTbl.AgencyID = AgencyTbl.AgencyID) as [NO OF BRANCHES], 
(SELECT COUNT(*) AS Expr1 FROM dbo.TourTbl 
WHERE  (dbo.BranchTbl.BranchID = BranchID)) AS [NO TOURS EVER] 

FROM dbo.AgencyTbl INNER JOIN dbo.BranchTbl ON dbo.AgencyTbl.AgencyID = dbo.BranchTbl.AgencyID 
GROUP BY AgencyTbl.AgencyName, AgencyTbl.AgencyID, dbo.BranchTbl.BranchID 
order by AgencyTbl.AgencyName 

，但如果我运行此我得到同样的机构重复，因为该组由branchid如下：

this estate agent 12 0 
this estate agent 12 0 
this estate agent 12 0 
this estate agent 12 0 
this estate agent 12 0 
this estate agent 12 0 
this estate agent 12 0 
this estate agent 12 2 
this estate agent 12 0 
this estate agent 12 0 
this estate agent 12 0 
this estate agent 12 0 
    next agency  47 2 
    next agency  47 4 
    next agency  47 1 
    next agency  47 1 

我怎么能只列出一个机构和总数属于该机构的分支机构，然后计算属于该分支机构的旅行总数并且不重复机构名称。

Answer 1

我假设“属于该分支的旅行总数”是指“属于该代理的所有分支的旅行总数”属于“？

如果是这样，您可以使用其中任何一种方法。

方法1：仅使用子查询，不加入到BranchTbl：

SELECT dbo.AgencyTbl.AgencyName AS [LIST OF EACH AGENCY], 
     (SELECT COUNT(*) 
      FROM BranchTbl 
      WHERE AgencyID = AgencyTbl.AgencyID 
     ) AS [NO OF BRANCHES], 
     (SELECT COUNT(*) 
      FROM dbo.TourTbl 
      WHERE BranchID IN 
        (SELECT BranchID 
         FROM dbo.BranchTbl 
        WHERE AgencyID = AgencyTbl.AgencyID 
       ) 
     ) AS [NO TOURS EVER] 
    FROM dbo.AgencyTbl 
GROUP 
    BY AgencyTbl.AgencyName, 
     AgencyTbl.AgencyID 
ORDER 
    BY AgencyTbl.AgencyName 
; 

方法2：只有使用连接时，不要使用子查询：

SELECT dbo.AgencyTbl.AgencyName AS [LIST OF EACH AGENCY], 
     COUNT(DISTINCT dbo.BranchTbl.BranchID) AS [NO OF BRANCHES], 
     COUNT(dbo.TourTbl.BranchTbl) AS [NO TOURS EVER] 
    FROM dbo.AgencyTbl 
    LEFT 
    JOIN dbo.BranchTbl 
    ON dbo.BranchTbl.AgencyID = dbo.AgencyTbl.AgencyID 
    LEFT 
    JOIN dbo.TourTbl 
    ON dbo.TourTbl.BranchID = dbo.BranchTbl.BranchID 
GROUP 
    BY AgencyTbl.AgencyName 
ORDER 
    BY AgencyTbl.AgencyName 
; 

有是其他一些方法—例如，您可以加入到BranchTbl，但使用SUM(SELECT COUNT(*) FROM ...)获得参观次数—，但我认为以上是最清楚的。

[免责声明：我没有测试过上述任何查询]

Answer 2

首先，你不需要你的一些子查询的，因为你已经做了JOIN。最重要的是，您正在分组所需的更多列。试试这个：

SELECT dbo.AgencyTbl.AgencyName AS [LIST OF EACH AGENCY], 
     COUNT(*) AS [NO OF BRANCHES], 
     COUNT(dbo.TourTbl.*) AS [NO TOURS EVER], 
     COUNT(CASE WHEN YEAR(DT_Started) = YEAR(GETDATE()) THEN dbo.TourTbl.BranchID ELSE NULL END) [NO OF TOURS YTD (Year To Date)] 
FROM dbo.AgencyTbl 
INNER JOIN dbo.BranchTbl 
ON dbo.AgencyTbl.AgencyID = dbo.BranchTbl.AgencyID 
LEFT JOIN dbo.TourTbl 
ON dbo.BranchTbl.BranchID = dbo.TourTbl.BranchID 
GROUP BY AgencyTbl.AgencyName 
ORDER BY AgencyTbl.AgencyName