1
我有一个页面,生成一个表,其内容将被检索使用.getJSON
。但我有一个变量要通过该条件查询。这里是我的代码,传递一个变量使用.getJSON条件SQL查询
<?php $cust_id = $_GET['cust_id']; ?>
<table class="display" id="invoice-disc-list" cellspacing="0" width="100%">
<thead>
<tr>
<th>INVOICE #</th>
<th>INVOICE DATE</th>
<th>SALESMAN</th>
<th>INVOICE AMOUNT</th>
<th>DISCOUNT</th>
</tr>
</thead>
</table>
<script>
$.getJSON('pages/lj_menu/monitoring/process/price_history_data.php', function(response) {
var custid = '<?php echo $cust_id; ?>';
// Initialize DataTables
$('#invoice-disc-list').DataTable({
iDisplayLength : 15,
processing: true,
data: response,
columns: [
{data: "INVOICE_NO"},
{data: "INVOICE_DATE"},
{data: "INVOICE_SALESMAN"},
{data: "INVOICE_AMOUNT"},
{data: "INVOICE_DISCOUNT"}
]
});
// Initialize AJAX onClick Data Send
window.someGlobalOrWhatever = response.balance;
});
</script>
如何发布var custid = '<?php echo $cust_id; ?>';
到price_history_data.php
,使表里面的数据只显示了基于custid
变量,我将数据发送包含查询..?再次
感谢您的帮助
通GET参数** **客户ID作为GET参数 –
你是什么意思 ?以及如何做到这一点? –
像这样'$ .getJSON(“pages/lj_menu/monitoring/process/price_history_data.php?custid = <?php echo $ cust_id;?>”,function(response)' –