我有4个oracle SQL查询，我想要在一个结果

Question

这4个查询产生所需的结果，但我想把这些查询包装成一个查询，返回每个查询作为水平列与垂直相应的查询结果。

我有限的所有查询到ROWNUM < = 20

SELECT * FROM (SELECT count(tl.usr) as "Antall oppslag" FROM TABLE tl WHERE 
tl.timestamp >= (sysdate - (1/24)) GROUP BY tl.usr ORDER BY count(tl.usr) desc) WHERE 
rownum <= 20; 

SELECT * FROM (SELECT count(tl.usr) as "Antall oppslag" FROM TABLE tl WHERE 
tl.timestamp >= (sysdate - (1)) GROUP BY tl.usr ORDER BY count(tl.usr) desc) WHERE 
rownum <= 20; 

SELECT * FROM (SELECT count(tl.usr) as "Antall oppslag" FROM TABLE tl WHERE 
tl.timestamp >= (sysdate - (7)) GROUP BY tl.usr ORDER BY count(tl.usr) desc) WHERE 
rownum <= 20; 

SELECT * FROM (SELECT count(tl.usr) as "Antall oppslag" FROM TABLE tl WHERE 
tl.timestamp >= (sysdate - (30)) GROUP BY tl.usr ORDER BY count(tl.usr) desc) WHERE 
rownum <= 20; 

人对如何做到这一点有什么建议？

编辑：我想指定我不希望结果在彼此之上。不同的查询必须是水平列，而他们各自的结果去vertically.a

Answer 1

通过他们的rownum加入他们的行列（记得别名ROWNUM）

select * from 
(
SELECT rownum rownr, a.* FROM (SELECT count(tl.usr) as "Antall oppslag" FROM TABLE tl WHERE 
tl.timestamp >= (sysdate - (1/24)) GROUP BY tl.usr ORDER BY count(tl.usr) desc) a WHERE 
rownum <= 20 
) a, 
(
SELECT rownum rownr, b.* FROM (SELECT count(tl.usr) as "Antall oppslag" FROM TABLE tl WHERE 
tl.timestamp >= (sysdate - (1)) GROUP BY tl.usr ORDER BY count(tl.usr) desc) b WHERE 
rownum <= 20 
) b, 
(
SELECT rownum rownr, c.* FROM (SELECT count(tl.usr) as "Antall oppslag" FROM TABLE tl WHERE 
tl.timestamp >= (sysdate - (7)) GROUP BY tl.usr ORDER BY count(tl.usr) desc) c WHERE 
rownum <= 20 
) c, 
(
SELECT rownum rownr, d.* FROM (SELECT count(tl.usr) as "Antall oppslag" FROM TABLE tl WHERE 
tl.timestamp >= (sysdate - (30)) GROUP BY tl.usr ORDER BY count(tl.usr) desc) d WHERE 
rownum <= 20 
) d 
where a.rownr = b.rownr 
and a.rownr = c.rownr 
and a.rownr = d.rownr