Oracle SQL - 不一致的查询结果

Question

我正在尝试编写一个基于employeeID（每个employeeID不同范围）的特定日期范围的Oracle SQL查询，然后为每个员工在该日期范围内的特定绩效指标数字求和。根据我的选择，我似乎对同一个employeeID的结果不一致。这是我的查询：

select c.employeeID, b.assessmentDate, c.startDate, c.endDate, 
sum(case when employeeProductivityMetric='15' then 1 else 0 end) as Metric1, 
sum(case when employeeProductivityMetric='20' then 1 else 0 end) as Metric2 
from assessmentTable b 
inner join performanceMetricTable c on b.badgeID = c.badgeID 
where b.assessmentDate between c.startDate and c.endDate 
group by c.employeeID, b.assessmentDate, c.startDate, c.endDate 
order by c.employeeID, b.assessmentDate; 

请注意，给定的employeeID可以与多个badgeID关联。

当我选择一个特定的雇员（比如2）通过添加以下where子句：

where c.employeeID=2 

我得到一些特别的号码Metric1和Metric2：

employeeID assessmentDate startDate endDate Metric1 Metric2 
2   02-Jul-15  01-Jul-15 31-Jul-15 4  5 

然而，当我做

where c.employeeID between 1 and 3 

我得到不同的员工2号码，如：

employeeID assessmentDate startDate endDate Metric1 Metric2 
2   02-Jul-15  01-Jul-15 31-Jul-15 3  0 

有没有人知道为什么会这样？我的查询设计有问题吗？

谢谢你的指点！

纳塔利娅

Answer 1

您可以通过检索详细记录调试这种类型的情况：

尝试最有可能比较以下查询

-- matched records for employeeID=2 
select c.employeeID, c.badgeID, b.assessmentDate, c.startDate, c.endDate, 
employeeProductivityMetric 
from assessmentTable b 
inner join performanceMetricTable c on b.badgeID = c.badgeID 
where b.assessmentDate between c.startDate and c.endDate 
     and c.employeeID=2 
order by c.employeeID, c.badgeID, b.assessmentDate; 

和

-- matched records for employeeID between 1 and 3 
select c.employeeID, c.badgeID, b.assessmentDate, c.startDate, c.endDate, 
employeeProductivityMetric 
from assessmentTable b 
inner join performanceMetricTable c on b.badgeID = c.badgeID 
where b.assessmentDate between c.startDate and c.endDate 
     and c.employeeID between 1 and 3 
order by c.employeeID, c.badgeID, b.assessmentDate 

，你会注意到badgeIds的差异由每个查询返回。