2015-05-28 66 views
0

我试图将以下json对象转换为表格,但Corona未能这样做并给出打印0。我尝试用“”替换“__type”:“Object”,以防止混淆,但没有运气。Corona未将json转换为表格

tempTable1 = '{"result":[{"__type":"Object","address":"95-97 Whitehorse Rd Blackburn VIC 3130","className":"allJobs","content":"Dr test","coord":{"__type":"GeoPoint","latitude":-37.817272,"longitude":145.149913},"createdAt":"2015-05-21T05:15:45.012Z","done":false,"email":"na","job":"psychologist","objectId":"PfKJkmIQKw","order":1,"phone":"0422031410","postcode":"3130","suburb":"Blackburn VIC","updatedAt":"2015-05-27T08:15:46.607Z","web":"na"},{"__type":"Object","address":"Suite 9 10-12 Prospect St Box Hill ","className":"allJobs","content":"Dr 2)","coord":{"__type":"GeoPoint","latitude":-37.817957,"longitude":145.118997},"createdAt":"2015-05-21T05:17:56.382Z","done":false,"email":"[email protected]","job":"lawyer","objectId":"xnLABEm5S4","order":1,"phone":"03 9890 0797","postcode":"3128","suburb":"Box Hill VIC","updatedAt":"2015-05-27T08:15:21.112Z","web":"na"}]}' 


local tables = json.decode(tempTable1) 
print(#tables) 

回答

0

我以错误的方式调用结果。因为它在其他表格中创建了一些表格。以下是正确的。

print (event.response.result[5].email) 
print (event.response.result[5].coord.latitude)