如何检查一个字符串是否包含数组中的单词然后回显？

Question

我有一个包含一个位置 如 活动，纽约开发商一句

在我的数组

我有位置

我要检查如果字符串包含从阵列中的位置，如果列表它然后回显出来

$string = 'Activities in New York for developers'; 
$array = array("New York","Seattle", "San Francisco"); 
if(0 == count(array_intersect(array_map('strtolower', explode(' ', $string)), $array))){ 

echo $location /*echo out location that is in the string on its own*/ 

} else { 

/*do nothing*/ 

} 

Answer 1

使用stripos

$string = 'Activities in New York for developers'; 
$array = array("New York","Seattle", "San Francisco"); 
foreach($array as $location) { 
    if(stripos($string, $location) !== FALSE) { 
     echo $string; 
     break; 
    } 
} 

Answer 2

遍历您的数组是这样的：

$string = 'Activities in New York for developers'; 
$array = array("New York","Seattle", "San Francisco"); 
//loop over locations 
foreach($array as $location) { 
    //strpos will return false if the needle ($location) is not found in the haystack ($string) 
    if(strpos($string, $location) !== FALSE) { 
     echo $string; 
     break; 
    } 
} 

编辑

如果你想回声出的位置只是改变$string与$location：

$string = 'Activities in New York for developers'; 
$array = array("New York","Seattle", "San Francisco"); 
//loop over locations 
foreach($array as $location) { 
    //strpos will return false if the needle ($location) is not found in the haystack ($string) 
    if(strpos($string, $location) !== FALSE) { 
     echo $location; 
     break; 
    } 
}