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Twitter的风格错误,我需要找到一种常见的方式与TastyPie例如以错误报告给我的用户在Twitter的看着这也是他们始终显示错误:Django的TastyPie
{"errors":[{"message":"Sorry, that page does not exist","code":34}]}
因此错误是一个数组的错误。
我试图做沿着相同的路线东西TastyPie这样的:
def is_valid(self, bundle, request=None):
errors = {}
# Check if user already exists before allowing API to create a new one.
this_email = bundle.data.get('email', None)
object_count = Member.objects.filter(email=this_email).count()
if object_count != 0:
errors['ERRORS'] = 'Duplicate email address'
return errors
但你可以看到它不是很干燥,输出是不正确的:
{"object_register":{"ERRORS":"Sorry, that page does not exist"}}
我有也试过:
reply = {}
reply['errors'] = [{'message': 'Sorry we could not log you in.'}]
return self.create_response(request, reply, HttpUnauthorized)
所以我的问题是,有可能实现'Twitter'风格输出的错误以干的方式使用Tatypie?如果有这样的例子吗?