3
我一直在用iOS 5.0的新NSLinguisticTagger在Xcode 4.2中摆弄。我用这个函数的目标是获取一个地址簿记录,然后将一个复合名称作为一个NSString来分发,就像ABRecordCopyCompositeName所做的一样,但是考虑到东亚语言和匈牙利语的命名顺序(最后一个而不是最后一个) )。这里的功能:NSLinguisticTagger内存泄漏
NSString *text = [self getLocalizedFullNameOfRecord:[contacts objectAtIndex:indexPath.section];
- (NSString *) getLocalizedFullNameOfRecord:(ABRecordRef) person
{
NSString *firstName = ABRecordCopyValue(person, kABPersonFirstNameProperty);
NSString *middleName = ABRecordCopyValue(person, kABPersonMiddleNameProperty);
NSString *lastName = ABRecordCopyValue(person, kABPersonLastNameProperty);
NSString *prefix = ABRecordCopyValue(person, kABPersonPrefixProperty);
NSString *suffix = ABRecordCopyValue(person, kABPersonSuffixProperty);
NSString *fullName = @"";
__block BOOL Asian;
// Apologies to all Hungarians who aren't actually Asian
__block NSArray *asianLanguages = [NSArray arrayWithObjects:@"zh-Hant", @"zh-Hans", @"ja", @"ko", @"hu", @"vi", nil];
[firstName enumerateLinguisticTagsInRange:NSMakeRange(0, firstName.length) scheme: NSLinguisticTagSchemeLanguage options: NSLinguisticTaggerOmitWhitespace orthography: nil usingBlock:^(NSString *tag, NSRange tokenRange, NSRange sentenceRange, BOOL *stop){
if ([asianLanguages containsObject:tag])
Asian = YES;
else
Asian = NO;
}];
if(prefix)
fullName = [fullName stringByAppendingFormat:@"%@ ", prefix];
if(Asian && lastName)
fullName = [fullName stringByAppendingFormat:@"%@ ", lastName];
else if(firstName)
fullName = [fullName stringByAppendingFormat:@"%@ ", firstName];
if(middleName)
fullName = [fullName stringByAppendingFormat:@"%@ ", middleName];
if(Asian && firstName)
fullName = [fullName stringByAppendingFormat:@"%@ ", firstName];
else if(lastName)
fullName = [fullName stringByAppendingFormat:@"%@ ", lastName];
if(suffix)
fullName = [fullName stringByAppendingFormat:@"%@", suffix];
[firstName release];
[middleName release];
[lastName release];
[prefix release];
[suffix release];
return fullName;
}
仪器告诉我,我一定泄漏16至32个字节具有这种功能的每次迭代,在enumerateLinguisticTagger(而不是块部分,显然)。由于NSLinguisticTagger的在线资源仅限于其类参考和单个教程,因此我不知道在哪里以及如何开始寻找泄漏。
请帮忙吗?
对于有用的代码片段+1。我正在看着这个(http://www.w3.org/International/questions/qa-personal-names),想知道我该怎么做,嘿,快到了,可怜的救援:-) – 2012-12-13 15:55:45