批处理如果声明错误

Question

我正在尝试使批量扫雷，但我有奇怪的错误。当我运行该文件时，它会放置5个地雷。然后它穿过其余的广场并检查每个广场附近有多少个地雷。我的问题是，它只感觉到向东南方向输出。东南码与任何其他方向的码不同。这对我来说非常混乱。似乎没有其他人有这个错误。这是一个输出示例：

M 0 1 0 0 
0 1 0 M 0 
M 0 M 0 0 
0 0 1 0 0 
0 0 0 M 0 

答案将不胜感激。

@echo off 
setlocal enableDelayedExpansion 
setlocal ENABLEEXTENSIONS 
title Batch Minesweeper 
color 80 
set setX=1 
set setY=1 
set testX=1 
set testY=1 
set plrX=1 
set plyY=1 
set mines=0 
set mineNum=0 
set N= 
set NE= 
set E= 
set SE= 
set S= 
set SW= 
set W= 
set NW= 
set rect1_1= 
set rect2_1= 
set rect3_1= 
set rect4_1= 
set rect5_1= 
set rect1_2= 
set rect2_2= 
set rect3_2= 
set rect4_2= 
set rect5_2= 
set rect1_3= 
set rect2_3= 
set rect3_3= 
set rect4_3= 
set rect5_3= 
set rect1_4= 
set rect2_4= 
set rect3_4= 
set rect4_4= 
set rect5_4= 
set rect1_5= 
set rect2_5= 
set rect3_5= 
set rect4_5= 
set rect5_5= 
set mine1_1=0 
set mine2_1=0 
set mine3_1=0 
set mine4_1=0 
set mine5_1=0 
set mine1_2=0 
set mine2_2=0 
set mine3_2=0 
set mine4_2=0 
set mine5_2=0 
set mine1_3=0 
set mine2_3=0 
set mine3_3=0 
set mine4_3=0 
set mine5_3=0 
set mine1_4=0 
set mine2_4=0 
set mine3_4=0 
set mine4_4=0 
set mine5_4=0 
set mine1_5=0 
set mine2_5=0 
set mine3_5=0 
set mine4_5=0 
set mine5_5=0 
cls 
echo Batch Minesweeper 
echo. 
echo [1] - Play 
echo [2] - Info 
echo [3] - Exit 
echo. 
echo Batch Minesweeper made by Matt Pauly 
choice /c 123 /n /m "" 
if %errorlevel%==1 goto startGame 
if %errorlevel%==1 goto info 
if %errorlevel%==1 goto end 

:startGame 
cls 
set /a ranX=%RANDOM% * 5/32768 + 1 
set /a ranY=%RANDOM% * 5/32768 + 1 
if not %mines%==5 (
    if !mine%ranX%_%ranY%!==0 (
     set mine%ranX%_%ranY%=M 
     set /a mines=%mines% + 1 
     goto startGame 
     ) 
    goto startGame 
    ) 
goto setup 

:setup 
cls 
echo Loading... 
set curVal=%setX%_%setY% 
if %curVal%==1_6 goto display 
if %setX%==6 (
    set setX=1 
    set /a setY=%setY% + 1 
    goto setup 
    ) 
if !mine%setX%_%setY%!==M (
    set /a setX=%setX% + 1 
    goto setup 
    ) 
set /a testY=%setY% + 1 
set testX=%setX%  
set N=!mine%testX%_%testY%! 
set /a testY=%setY% + 1 
set /a testX=%setX% + 1 
set NE=!mine%testX%_%testY%!  
set testY=%setY% 
set /a testX=%setX% + 1 
set E=!mine%testX%_%testY%! 
set /a testY=%setY% + 1 
set /a testX=%setX% - 1 
set SE=!mine%testX%_%testY%!  
set testY=%setY% 
set /a testX=%setX% - 1 
set S=!mine%testX%_%testY%! 
set /a testY=%setY% - 1 
set /a testX=%setX% - 1 
set SW=!mine%testX%_%testY%!  
set /a testY=%setY% + 1 
set testX=%setX%  
set W=!mine%testX%_%testY%! 
set /a testY=%setY% - 1 
set /a testX=%setX% + 1 
set NW=!mine%testX%_%testY%! 
set mineNum=0 
if defined N if "%N%"=="M" set /a mineNum=%mineNum% + 1 
if defined NW if "%NW%"=="M" set /a mineNum=%mineNum% + 1 
if defined W if "%W%"=="M" set/a mineNum=%mineNum% + 1 
if defined SW if "%S%"=="M" set /a mineNum=%mineNum% + 1 
if defined S if "%S%"=="M" set /a mineNum=%mineNum% + 1 
if defined SE if "%SE%"=="M" set /a mineNum=%mineNum% + 1 
if defined E if "%E%"=="M" set /a mineNum=%mineNum% + 1 
if defined NE if "%NE%"=="M" set /a mineNum=%mineNum% + 1 
set mine%setX%_%setY%=%mineNum% 
set /a setX=%setX% + 1 
goto setup 

:display  
cls 
::echo 5 %rect1_5% %rect2_5% %rect3_5% %rect4_5% %rect5_5% 
::echo. 
::echo 4 %rect1_4% %rect2_4% %rect3_4% %rect4_4% %rect5_4% 
::echo. 
::echo 3 %rect1_3% %rect2_3% %rect3_3% %rect4_3% %rect5_3% 
::echo. 
::echo 2 %rect1_2% %rect2_2% %rect3_2% %rect4_2% %rect5_2% 
::echo. 
::echo 1 %rect1_1% %rect2_1% %rect3_1% %rect4_1% %rect5_1% 
::echo. 
::echo  a b c d e 
echo 5 %mine1_5% %mine2_5% %mine3_5% %mine4_5% %mine5_5% 
echo. 
echo 4 %mine1_4% %mine2_4% %mine3_4% %mine4_4% %mine5_4% 
echo. 
echo 3 %mine1_3% %mine2_3% %mine3_3% %mine4_3% %mine5_3% 
echo. 
echo 2 %mine1_2% %mine2_2% %mine3_2% %mine4_2% %mine5_2% 
echo. 
echo 1 %mine1_1% %mine2_1% %mine3_1% %mine4_1% %mine5_1% 
echo. 
echo  a b c d e 
pause 

:info 

:end 
exit 

Answer 1

您的主要问题是行尾空格。在传统的set语句中，任何尾部空格都包含在分配的值中，并且"M"和"M "是完全不同的东西，因此如果您有set X=!something!，则分配的值与set X=!something!分配的值不同。

您还有一个问题，在您将X与您的Y混淆。例如，设置W使用X和Y+1完成 - 与设置N相同。这应该是X-1和Y。