嗨,我创建一个dockwidget,我开始隐藏。问题是之后我无法显示它,而我可以从isHidden()函数正确地获取状态。奇怪的是,如果我启动dockwidget而不是隐藏,它的工作原理是完美的。我包括一个重现这种奇怪行为的例子。在qt中显示隐藏dockwidget
mainwindow.h
#ifndef MAINWINDOW_H
#define MAINWINDOW_H
#include <QMainWindow>
#include <QtGui>
namespace Ui {
class MainWindow;
}
class MainWindow : public QMainWindow
{
Q_OBJECT
public:
explicit MainWindow(QWidget *parent = 0);
~MainWindow();
private slots:
void showDock();
private:
Ui::MainWindow *ui;
QDockWidget *dock;
QPushButton *button;
};
#endif // MAINWINDOW_H
mainwindow.cpp
#include "mainwindow.h"
#include "ui_mainwindow.h"
MainWindow::MainWindow(QWidget *parent) :
QMainWindow(parent),
ui(new Ui::MainWindow)
{
ui->setupUi(this);
// QMainWindow mainWindow;
// QDockWidget *dock = new QDockWidget(&mainWindow);
QDialog *dockDialog = new QDialog(this); // <---------edit: you need to create a parent widget for the dock
dock = new QDockWidget(dockDialog);
dock->setStyleSheet("QDockWidget { font: bold }");
dock->setFloating(true);
dock->setFeatures(QDockWidget::DockWidgetVerticalTitleBar | QDockWidget::DockWidgetFloatable | QDockWidget::DockWidgetMovable);
QAbstractButton *floatButton = dock->findChild<QAbstractButton*>("qt_dockwidget_floatbutton");
if(floatButton)
floatButton->hide();
dock->setAllowedAreas(Qt::NoDockWidgetArea);
dock->setWindowTitle("Tools");
this->addDockWidget(Qt::TopDockWidgetArea, dock, Qt::Vertical);
QMainWindow *window = new QMainWindow(dock); // <------edit: set the dock to be the parent for the window
window->setWindowFlags(Qt::Widget);
QToolBar *bar = new QToolBar(window);
bar->setMovable(false);
bar->addAction("Select");
bar->addAction("Polygon");
bar->addAction("Brush");
bar->addAction("Erazer");
bar->addSeparator();
bar->addAction("Mark");
bar->setSizePolicy(QSizePolicy::Fixed, QSizePolicy::Fixed);
bar->setOrientation(Qt::Vertical);
window->addToolBar(Qt::LeftToolBarArea, bar);
window->setSizePolicy(QSizePolicy::Fixed, QSizePolicy::Fixed);
window->setParent(dock);
dock->setWidget(window);
dock->hide(); // <------------ comment this line and it will work, edit: you do not need to do that anymore, it is working nicely now
button = new QPushButton("show", this);
button->setCheckable(true);
QObject::connect(button, SIGNAL(clicked()), this, SLOT(showDock()));
}
MainWindow::~MainWindow()
{
delete ui;
}
void MainWindow::showDock()
{
// qDebug() << "hello";
if(button->isChecked()){
if(dock->isHidden()){
qDebug() << "hidden";
dock->setFloating(true); // <-----edit: you need to add these lines in order to be able to see the dialog that contains the dock widget, i do not know why i need to that again since in the initialization i already specifying that my dock is floatable
QAbstractButton *floatButton = dock->findChild<QAbstractButton*>("qt_dockwidget_floatbutton"); // <---------edit: add this lines in order to get rid off the floating button
if(floatButton)
floatButton->hide(); // <----edit: the same as previous
dock->show();
}
}
if(!button->isChecked()){
if(!dock->isHidden()){
qDebug() << "not hidden";
dock->hide();
}
}
}
因为它现在是dockwidget未在屏幕出现在上面的代码。如果您尝试评论我在mainwindow.cpp中指定的行,它可以工作,但重点是我想要启动隐藏的dockwidget。有人有任何想法,发生了什么。
谢谢。
@ Nemanja的建议没有起作用,正如我想要的,但他提供了一些提示,以使其按照我的意愿工作。我已经添加了修改。我不知道这是否是正确的方式,因为我正在这样做,但它现在起作用。谢谢 – ThT