2013-02-05 59 views
1

嗨,我创建一个dockwidget,我开始隐藏。问题是之后我无法显示它,而我可以从isHidden()函数正确地获取状态。奇怪的是,如果我启动dockwidget而不是隐藏,它的工作原理是完美的。我包括一个重现这种奇怪行为的例子。在qt中显示隐藏dockwidget

mainwindow.h

#ifndef MAINWINDOW_H 
#define MAINWINDOW_H 

#include <QMainWindow> 
#include <QtGui> 

namespace Ui { 
class MainWindow; 
} 

class MainWindow : public QMainWindow 
{ 
    Q_OBJECT 

public: 
    explicit MainWindow(QWidget *parent = 0); 
    ~MainWindow(); 
private slots: 

    void showDock(); 
private: 
    Ui::MainWindow *ui; 

    QDockWidget *dock; 
    QPushButton *button; 


}; 

#endif // MAINWINDOW_H 

mainwindow.cpp

#include "mainwindow.h" 
#include "ui_mainwindow.h" 

MainWindow::MainWindow(QWidget *parent) : 
    QMainWindow(parent), 
    ui(new Ui::MainWindow) 
{ 
    ui->setupUi(this); 

// QMainWindow mainWindow; 
// QDockWidget *dock = new QDockWidget(&mainWindow); 
    QDialog *dockDialog = new QDialog(this); // <---------edit: you need to create a parent widget for the dock 
    dock = new QDockWidget(dockDialog); 

    dock->setStyleSheet("QDockWidget { font: bold }"); 
    dock->setFloating(true); 
    dock->setFeatures(QDockWidget::DockWidgetVerticalTitleBar | QDockWidget::DockWidgetFloatable | QDockWidget::DockWidgetMovable); 
    QAbstractButton *floatButton = dock->findChild<QAbstractButton*>("qt_dockwidget_floatbutton"); 
    if(floatButton) 
     floatButton->hide(); 

    dock->setAllowedAreas(Qt::NoDockWidgetArea); 
    dock->setWindowTitle("Tools"); 

    this->addDockWidget(Qt::TopDockWidgetArea, dock, Qt::Vertical); 

    QMainWindow *window = new QMainWindow(dock); // <------edit: set the dock to be the parent for the window 
    window->setWindowFlags(Qt::Widget); 
    QToolBar *bar = new QToolBar(window); 

    bar->setMovable(false); 
    bar->addAction("Select"); 
    bar->addAction("Polygon"); 
    bar->addAction("Brush"); 
    bar->addAction("Erazer"); 
    bar->addSeparator(); 
    bar->addAction("Mark"); 
    bar->setSizePolicy(QSizePolicy::Fixed, QSizePolicy::Fixed); 
    bar->setOrientation(Qt::Vertical); 

    window->addToolBar(Qt::LeftToolBarArea, bar); 
    window->setSizePolicy(QSizePolicy::Fixed, QSizePolicy::Fixed); 

    window->setParent(dock); 
    dock->setWidget(window); 
    dock->hide();   // <------------ comment this line and it will work, edit: you do not need to do that anymore, it is working nicely now 

    button = new QPushButton("show", this); 
    button->setCheckable(true); 

    QObject::connect(button, SIGNAL(clicked()), this, SLOT(showDock())); 
} 

MainWindow::~MainWindow() 
{ 
    delete ui; 
} 


void MainWindow::showDock() 
{ 
// qDebug() << "hello"; 
    if(button->isChecked()){ 
     if(dock->isHidden()){ 
      qDebug() << "hidden"; 
     dock->setFloating(true); // <-----edit: you need to add these lines in order to be able to see the dialog that contains the dock widget, i do not know why i need to that again since in the initialization i already specifying that my dock is floatable 
     QAbstractButton *floatButton = dock->findChild<QAbstractButton*>("qt_dockwidget_floatbutton"); // <---------edit: add this lines in order to get rid off the floating button 
     if(floatButton) 
      floatButton->hide(); // <----edit: the same as previous 
     dock->show(); 
     } 
    } 

    if(!button->isChecked()){ 
     if(!dock->isHidden()){ 
      qDebug() << "not hidden"; 
      dock->hide(); 
     } 
    } 
} 

因为它现在是dockwidget未在屏幕出现在上面的代码。如果您尝试评论我在mainwindow.cpp中指定的行,它可以工作,但重点是我想要启动隐藏的dockwidget。有人有任何想法,发生了什么。

谢谢。

+0

@ Nemanja的建议没有起作用,正如我想要的,但他提供了一些提示,以使其按照我的意愿工作。我已经添加了修改。我不知道这是否是正确的方式,因为我正在这样做,但它现在起作用。谢谢 – ThT

回答

0

QDock控件的父项应该是您的window控件,而不是MainWindow类的对象。

所以,你需要替换此:

dock = new QDockWidget(this); 

这一点:当你按在第一种情况下显示按钮,也

QMainWindow *window = new QMainWindow(0); // I smell a potential leak here (set the parent!) 
dock = new QDockWidget(window); 

控制是可见的,但它是外面的某个地方窗口,所以你可能看不到它。另外,不需要在已经继承QMainWindow的类内部创建QMainWindow的单独实例。

0

我看到你show()/ hide()你的dockwidget。我没有尝试过,但也许你应该隐藏并显示dockwdiget的方法QDockWidget::toggleViewAction