方法在swift 4迅速4

Question

Swiftling在斯威夫特4不再有效。

Method 'initialize()' defines Objective-C class method 'initialize', which is not permitted by Swift

这是我已经找到了解决方案，所以想离开的问题和回答别人。

Answer 1

初始化（）不再暴露：Method 'initialize()' defines Objective-C class method 'initialize', which is not permitted by Swift

所以这样做，现在是通过公共静态方法来运行你的调酒代码。

例如

在扩展名： （此扩展用于在动工开放源码：https://github.com/kickstarter/ios-oss/blob/master/Library/DataSource/UIView-Extensions.swift）

private var hasSwizzled = false 

extension UIView { 
    final public class func doBadSwizzleStuff() { 
     guard !hasSwizzled else { return } 

     hasSwizzled = true 
     swizzle(self) /* This is pseudo - run your method here */ 
    } 
} 

在应用程序委托： （此方法是在动工打开用于源代码：https://github.com/kickstarter/ios-oss/blob/7c827770813e25cc7f79a28fa151cd713efe936f/Kickstarter-iOS/AppDelegate.swift#L33）

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: UIApplicationLaunchOptionsKey: Any]?) -> Bool 
{ 
    UIView.doBadSwizzleStuff() 
} 

---

另一种方法是使用一个单例：如果你有机会到AppDelegate的源代码

extension UIView { 
    static let shared : UIViewController = { 
     $0.initialize() 
     return $0 
    }(UIViewController()) 

    func initialize() { 
     // make sure this isn't a subclass 
     guard self === UIViewController.self else { return } 

     let swizzleClosure:() = { 
      UIViewController().swizzle() /* This is pseudo - run your method here */ 
     }() 
     swizzleClosure 
    } 
} 

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: UIApplicationLaunchOptionsKey: Any]?) -> Bool 
{ 
    _ = UIViewController.shared 
}