查找小时之间的差异

Question

我有两个小时和几分钟：

我从用户那里得到了这个时间。那你的开始时间和结束时间是什么。

1) 10:00 AM 
2) 06:00 PM 

现在我必须找到用户总工作时间。意思是取得 总时间：8:00

我该如何得到它？

我定这个代码在Objective C.

Answer 1

我认为这将帮助你。

NSString *time1 = @"10.00 pm"; 
NSString *time2 = @"06.00 pm"; 
NSDate *date1; 
NSDate *date2; 
{ 
    NSDateFormatter *formatter = [[NSDateFormatter alloc] init]; 
    [formatter setDateFormat:@"hh.mm a"]; 
    date1 = [formatter dateFromString:time1]; 
    date2 = [formatter dateFromString:time2]; 
    [formatter release]; 
} 
NSTimeInterval interval = [date1 timeIntervalSinceDate: date2]; //[date1 timeIntervalSince1970] - [date2 timeIntervalSince1970]; 
    int hour = interval/3600; 
int minute = (int)interval % 3600/60; 

NSLog(@"%@ %dh %dm", interval<0?@"-":@"+", ABS(hour), ABS(minute)); 

Answer 2

试试看这样！

let calendar = NSCalendar.current 

    let datecomponents = calendar.dateComponents([.hour], from: start as Date, to: someDateTime as Date) 
    let hours = datecomponents.hour! 
    print("hours: \(hours)") 

Answer 3

试试这个功能

-(NSString *)startTime:(NSString *)startTime AndWithAndTime:(NSString *)endTime{ 
    NSDateFormatter *formatter = [[NSDateFormatter alloc] init]; 
    [formatter setDateFormat:@"hh:mm a"]; 
    NSDate *date1 = [formatter dateFromString:startTime]; 
    NSDate *date2 = [formatter dateFromString:endTime]; 
    NSTimeInterval interval = [date2 timeIntervalSinceDate:date1]; 
    int hours = (int)interval/3600;    // integer division to get the hours part 
    int minutes = (interval - (hours*3600))/60; // interval minus hours part (in seconds) divided by 60 yields minutes 
    NSString *timeDiff = [NSString stringWithFormat:@"%d:%02d", hours, minutes]; 
    return timeDiff; 
} 

NSLog(@"%@",[self startTime:@"10:00 AM" AndWithAndTime:@"06:00 PM"]);